BODMAS Questions for class 5

In this post, we will provide you with BODMAS Questions for Class 5 with answers, which you can practice so as to improve your understanding of the topic.

We use the acronym “BODMAS” to make a mathematical equation with two or more operations simpler. The letters B, O, D, M, A, and S stand for brackets, orders (powers/indices or roots), division, multiplication, addition, and subtraction, respectively. The students can practice the various types of questions in the section below on simplifications to gain greater insight into the topic.

BODMAS Questions for class 5 with Answers

Remember the below table for the correct implementation of the BODMAS rule.

1.  12- (7 – 9 ÷ 3) 

Solution: 12- (7 – 9 ÷ 3)
= 12- (7 – 3) (As per BODMAS rule first division shall be performed)
= 12-4 (Performing subtraction)
=8

2. 45 + 28 ÷ (7 – 3) 

Solution: 45 +28 ÷(7 – 3)
= 45 +28 ÷(7 – 3)
= 45 +28 ÷(4) (Removing small bracket )
=45 +7 (Performing Division) =52 (Performing Addition)

3. 32– 1/2{5 + 4 – (3 + 2 – 1 + 3)} 

Solution: 32– 1/2{5 + 4 – (3 + 2 – 1 + 3)} 
= 32– 1/2{5 + 4 – 7}  (Removing small bracket)
= 32– 1/2{2}  (Removing curly bracket)
= 32– 1  (Performing Division) = 31 (Performing Subtraction)

4. 27 – [48- {50 – (15 – 13 – 2)}] 

27 – [48- {50 – (15 – 13 – 2)}] 
= 27 – [48- {50 – 0}]  (Removing small bracket)
= 27 – [48- 50]  (Removing curly bracket)
= 27 – [-2]   (Removing Square bracket) = 29 (Performing Addition)

5. 50- [18 – {14 – (15 – 4 ÷ 2 x 2)}] 

 = 50- [18 – {14 – (15 – 4 ÷ 2 x 2)}]  =  50- [18 – {14 – 11}]   (Removing Small bracket ) = 50- [18 – 3]   (Removing curly bracket)
=  50- 15 (Removing Square bracket)
= 35 (Performing Subtraction)

6. 62- [38 – {60 ÷ 3 – (6 – 9 ÷ 3) ÷ 3}]

 = 62- [38 – {60 ÷ 3 – 3 ÷ 3}] (Removing Small bracket ) =  62- [38 – 19]   (Removing curly bracket) = 62- 19 (Removing Square bracket)
= 43 (Performing Subtraction)

7. 47- [23 – {23 – (23 – 23 – 23)}] 

= 47-[23-{23-(23-23-23)}]
= 47-[23-{23-(0-23)}]
= 47-[23-{23-(-23)}]
= 47-[23-{23–23}]
= 47-[23-{23+23}]
= 47-[23-{46}]
= 47-[23-46]
= 47-[-23]
= 47–23
= 47+23
= 70

8. 4 + (1÷ 5) [{-10 x (25 – 13 – 3)} ÷ (-5)] 

= 4+(1÷ 5)[{-10(25-13-3)}÷ (-5)]
= 4+(1÷ 5)[{-10(25-13-3)}÷ (-5)]
= 4+(1÷ 5)[{-10(25-13-3)}÷ (-5)]
= 4+(1÷ 5)[{-10(12-3)}÷ (-5)]
= 4+(1÷ 5)[-90÷(-5)]
= 4+(1÷5)*18
= 4+3.6
= 7.6

9. 22 – (1/4){-5 – (- 48) ÷ (-16)} 

= 22-(1/4){-5-(-48)/(-16)} =
= 22-(1/4){-5+48/(-16)}
= 22-(1/4){-5-3} =
= 22-(1/4)-8 =
= 22-(-2)
= 22+2
= 24

10. 45- (-3) {-2 – 8 – 3} ÷ 3{5 + (-2) (-1)} 

= 45-(-3){-2-8-3}÷ 3{5+(-2)(-1)}
= 45+3{-2-8-3}÷ 3{5+(-2)(-1)}
= 45+3{-13}{÷ 3{5+(-2)(-1)}
= 45+-39÷ 3{5+-2(-1)}
= 45+-39÷ 3{5+2} = 45+-13*7
= 45-91
= -46

11. 14*7+32/8+14

= 14*7+32/8+14
= 98+32/8+14
= 98+4+14
= 102+14
= 116

BODMAS Questions for class 5 pdf with solution