Simplification Questions for Class 5 with Answers (BODMAS & Brackets)

Simplification Questions for Class 5 with Answers: Practise 20 solved simplification problems covering round brackets ( ), curly brackets { }, square brackets [ ], vinculum (bar bracket), and the BODMAS rule, plus a free printable PDF worksheet.

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Simplification Questions for Class 5 with Answers

BODMAS Order of Operations for Class 5 Simplification

To simplify any mathematical expression with brackets and multiple operations, follow the BODMAS sequence from top to bottom:

LetterMeaningSymbols / Order
BBrackets (after Vinculum bar)Vinculum (โ€พ), then ( ), then { }, then [ ]
OOrder / OfOf, powers, indices, or roots
DDivisionรท or /
MMultiplicationร— or *
AAddition+
SSubtractionโˆ’

For expressions without brackets, you can also practise our DMAS Questions for Class 5 and BODMAS Questions for Class 5.

20 Solved Simplification Questions for Class 5 with Answers

Work through each Class 5 simplification problem below and compare your steps with the solution:

1. Simplify: 12 โˆ’ (7 โˆ’ 9 รท 3)
Solution: 12 โˆ’ (7 โˆ’ 9 รท 3)
= 12 โˆ’ (7 โˆ’ 3)  (Inside bracket, perform division first: 9 รท 3 = 3)
= 12 โˆ’ 4  (Remove small bracket: 7 โˆ’ 3 = 4)
= 8


2. Simplify: 45 + 28 รท (7 โˆ’ 3)
Solution: 45 + 28 รท (7 โˆ’ 3)
= 45 + 28 รท 4  (Removing small bracket: 7 โˆ’ 3 = 4)
= 45 + 7  (Performing division: 28 รท 4 = 7)
= 52


3. Simplify: 32 โˆ’ 1/2{5 + 4 โˆ’ (3 + 2 โˆ’ 1 + 3)}
Solution: 32 โˆ’ 1/2{5 + 4 โˆ’ (3 + 2 โˆ’ 1 + 3)}
= 32 โˆ’ 1/2{5 + 4 โˆ’ 7}  (Removing small bracket: 3 + 2 โˆ’ 1 + 3 = 7)
= 32 โˆ’ 1/2{2}  (Removing curly bracket: 9 โˆ’ 7 = 2)
= 32 โˆ’ 1  (Performing multiplication/division: 1/2 ร— 2 = 1)
= 31


4. Simplify: 27 โˆ’ [48 โˆ’ {50 โˆ’ (15 โˆ’ 13 โˆ’ 2)}]
Solution: 27 โˆ’ [48 โˆ’ {50 โˆ’ (15 โˆ’ 13 โˆ’ 2)}]
= 27 โˆ’ [48 โˆ’ {50 โˆ’ 0}]  (Removing small bracket: 15 โˆ’ 13 โˆ’ 2 = 0)
= 27 โˆ’ [48 โˆ’ 50]  (Removing curly bracket)
= 27 โˆ’ [โˆ’2]  (Removing square bracket)
= 27 + 2 = 29


5. Simplify: 50 โˆ’ [18 โˆ’ {14 โˆ’ (15 โˆ’ 4 รท 2 ร— 2)}]
Solution: 50 โˆ’ [18 โˆ’ {14 โˆ’ (15 โˆ’ 4 รท 2 ร— 2)}]
= 50 โˆ’ [18 โˆ’ {14 โˆ’ (15 โˆ’ 2 ร— 2)}]  (Division inside small bracket: 4 รท 2 = 2)
= 50 โˆ’ [18 โˆ’ {14 โˆ’ 11}]  (Removing small bracket: 15 โˆ’ 4 = 11)
= 50 โˆ’ [18 โˆ’ 3]  (Removing curly bracket: 14 โˆ’ 11 = 3)
= 50 โˆ’ 15 = 35


6. Simplify: 62 โˆ’ [38 โˆ’ {60 รท 3 โˆ’ (6 โˆ’ 9 รท 3) รท 3}]
Solution: 62 โˆ’ [38 โˆ’ {60 รท 3 โˆ’ (6 โˆ’ 9 รท 3) รท 3}]
= 62 โˆ’ [38 โˆ’ {60 รท 3 โˆ’ 3 รท 3}]  (Removing small bracket: 6 โˆ’ 3 = 3)
= 62 โˆ’ [38 โˆ’ {20 โˆ’ 1}]  (Performing divisions inside curly bracket)
= 62 โˆ’ [38 โˆ’ 19]  (Removing curly bracket)
= 62 โˆ’ 19 = 43


7. Simplify: 47 โˆ’ [23 โˆ’ {23 โˆ’ (23 โˆ’ 23 โˆ’ 23)}]
Solution: 47 โˆ’ [23 โˆ’ {23 โˆ’ (23 โˆ’ 23 โˆ’ 23)}]
= 47 โˆ’ [23 โˆ’ {23 โˆ’ (0 โˆ’ 23)}]
= 47 โˆ’ [23 โˆ’ {23 โˆ’ (โˆ’23)}]
= 47 โˆ’ [23 โˆ’ {23 + 23}] = 47 โˆ’ [23 โˆ’ 46]
= 47 โˆ’ [โˆ’23] = 47 + 23 = 70


8. Simplify: 4 + (1 รท 5)[{โˆ’10 ร— (25 โˆ’ 13 โˆ’ 3)} รท (โˆ’5)]
Solution: 4 + (1 รท 5)[{โˆ’10 ร— (25 โˆ’ 13 โˆ’ 3)} รท (โˆ’5)]
= 4 + (1 รท 5)[{โˆ’10 ร— 9} รท (โˆ’5)]  (Removing small bracket: 25 โˆ’ 13 โˆ’ 3 = 9)
= 4 + (1 รท 5)[โˆ’90 รท (โˆ’5)]  (Removing curly bracket)
= 4 + (1 รท 5) ร— 18  (Removing square bracket: โˆ’90 รท โˆ’5 = 18)
= 4 + 3.6 = 7.6


9. Simplify: 22 โˆ’ (1/4){โˆ’5 โˆ’ (โˆ’48) รท (โˆ’16)}
Solution: 22 โˆ’ (1/4){โˆ’5 โˆ’ (โˆ’48) รท (โˆ’16)}
= 22 โˆ’ (1/4){โˆ’5 โˆ’ 3}  (Performing division: โˆ’48 รท โˆ’16 = 3)
= 22 โˆ’ (1/4)(โˆ’8)
= 22 โˆ’ (โˆ’2) = 22 + 2 = 24


10. Simplify: 45 โˆ’ (โˆ’3){โˆ’2 โˆ’ 8 โˆ’ 3} รท 3{5 + (โˆ’2)(โˆ’1)}
Solution: 45 โˆ’ (โˆ’3){โˆ’2 โˆ’ 8 โˆ’ 3} รท 3{5 + (โˆ’2)(โˆ’1)}
= 45 + 3{โˆ’13} รท 3{5 + 2}
= 45 + (โˆ’39) รท 3 ร— 7
= 45 โˆ’ 13 ร— 7 = 45 โˆ’ 91 = โˆ’46


11. Simplify: 14 ร— 7 + 32 รท 8 + 14
Solution: 14 ร— 7 + 32 รท 8 + 14
= 14 ร— 7 + 4 + 14  (Performing division: 32 รท 8 = 4)
= 98 + 4 + 14  (Performing multiplication: 14 ร— 7 = 98)
= 102 + 14 = 116


12. Simplify: 30 รท 6 + 10 โˆ’ 2 ร— 5
Solution: 30 รท 6 + 10 โˆ’ 2 ร— 5
= 5 + 10 โˆ’ 2 ร— 5  (Division: 30 รท 6 = 5)
= 5 + 10 โˆ’ 10  (Multiplication: 2 ร— 5 = 10)
= 15 โˆ’ 10 = 5


13. Simplify: 48 รท 16 ร— 2 + 17 โˆ’ 9
Solution: 48 รท 16 ร— 2 + 17 โˆ’ 9
= 3 ร— 2 + 17 โˆ’ 9  (Division: 48 รท 16 = 3)
= 6 + 17 โˆ’ 9  (Multiplication: 3 ร— 2 = 6)
= 23 โˆ’ 9 = 14


14. Simplify: (18 + 10) โˆ’ (3 ร— 6)
Solution: (18 + 10) โˆ’ (3 ร— 6)
= 28 โˆ’ 18  (Solving both brackets first)
= 10


15. Simplify: (10 ร— 8) รท (20 รท 5)
Solution: (10 ร— 8) รท (20 รท 5)
= 80 รท 4  (Solving brackets: 10 ร— 8 = 80 and 20 รท 5 = 4)
= 20


16. Simplify: {20 โˆ’ (24 โˆ’ 10)} + 7
Solution: {20 โˆ’ (24 โˆ’ 10)} + 7
= {20 โˆ’ 14} + 7  (Removing small bracket)
= 6 + 7 = 13


17. Simplify: {20 + (15 + 5)} โˆ’ 5
Solution: {20 + (15 + 5)} โˆ’ 5
= {20 + 20} โˆ’ 5  (Removing small bracket)
= 40 โˆ’ 5 = 35


18. Simplify: 27 โˆ’ [18 โˆ’ {16 โˆ’ (5 โˆ’ 4-1 bar)}]
Solution: First solve the vinculum (bar) over 4 โˆ’ 1 = 3:
= 27 โˆ’ [18 โˆ’ {16 โˆ’ (5 โˆ’ 3)}]
= 27 โˆ’ [18 โˆ’ {16 โˆ’ 2}]  (Removing small bracket: 5 โˆ’ 3 = 2)
= 27 โˆ’ [18 โˆ’ 14]  (Removing curly bracket: 16 โˆ’ 2 = 14)
= 27 โˆ’ 4 = 23


19. Simplify: 2[19 โˆ’ {7 + (12 รท 4)}]
Solution: 2[19 โˆ’ {7 + (12 รท 4)}]
= 2[19 โˆ’ {7 + 3}]  (Removing small bracket: 12 รท 4 = 3)
= 2[19 โˆ’ 10]  (Removing curly bracket: 7 + 3 = 10)
= 2 ร— 9 = 18


20. Simplify: [{(30 โˆ’ 9-6 bar) รท 3} ร— 6 + 6]
Solution: First solve the vinculum (bar) over 9 โˆ’ 6 = 3:
= [{(30 โˆ’ 3) รท 3} ร— 6 + 6]
= [{27 รท 3} ร— 6 + 6]  (Removing small bracket: 30 โˆ’ 3 = 27)
= [9 ร— 6 + 6]  (Removing curly bracket: 27 รท 3 = 9)
= [54 + 6] = 60


Download Simplification Questions for Class 5 PDF with Solutions

Frequently Asked Questions on Class 5 Simplification

In what order are brackets solved in Class 5 simplification questions?

Always solve the vinculum or bar bracket first, followed by round brackets ( ), then curly braces { }, and finally square brackets [ ]. Inside each bracket, apply the DMAS order: Division, Multiplication, Addition, and Subtraction.

What is the difference between BODMAS and PEDMAS?

Both rules give the same result. BODMAS is used in India and stands for Brackets, Order/Of, Division, Multiplication, Addition, and Subtraction, whereas PEDMAS is used in the US and stands for Parentheses, Exponents, Division, Multiplication, Addition, and Subtraction.

Where can I find Class 5 simplification questions with brackets PDF?

You can download the free Simplification Worksheet 1 for Class 5 PDF directly from the download section on this page at ncertbookspdf.com, which includes bracket problems and complete worked-out answers.

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