DAV Class 7 Maths Chapter 12 Brain Teasers Solutions: Data Handling (with HOTS & Value Based Questions)

Complete step-by-step solutions for DAV Class 7 Secondary Mathematics Chapter 12: Data Handling (Brain Teasers, HOTS & Value Based Questions). Includes detailed calculations for Mean, Median, Mode, Range, frequency distributions, bar graphs, Higher Order Thinking Skills (HOTS), and Value-Based Questions (VBQs) aligned strictly with the DAV Education Board curriculum.

DAV Class 7 Maths Chapter 12: all worksheets  All Class 7 Maths chapters →

💬 📲 Share with Classmates & Study Groups:

📑 Quick Navigation & Worksheet Directory

Q.1. (A) Tick (✓) the correct option

(i) If the mean of 7, 4, x, and 10 is 8, the value of x is:

  • (a) 13
  • (b) 11
  • (c) 12
  • (d) 9
Step-by-step Solution:
Mean = (Sum of observations) ÷ (Number of observations)
8 = (7 + 4 + x + 10)/4
8 = (21 + x)/4
⇒ 21 + x = 8 × 4 = 32
⇒ x = 32 − 21 = 11.
Correct Option: (b) 11

(ii) The observation that occurs maximum number of times in a data set is called:

  • (a) Range
  • (b) Median
  • (c) Mode
  • (d) Mean
Reason: The value occurring with the highest frequency in a data collection is defined as the Mode.
Correct Option: (c) Mode

(iii) The heights (in cm) of 6 students in a class are 145, 152, 148, 150, 153, 146. The median height is:

  • (a) 149 cm
  • (b) 151 cm
  • (c) 148 cm
  • (d) 150 cm
Step-by-step Solution:
1. Arrange data in ascending order: 145, 146, 148, 150, 152, 153.
2. Total observations n = 6 (even).
3. Median = Average of 3rd and 4th terms:
= (148 + 150)/2 = 298/2 = 149 cm.
Correct Option: (a) 149 cm

(iv) The difference between the highest and lowest observations in a data set is known as:

  • (a) Frequency
  • (b) Mean
  • (c) Range
  • (d) Class mark
Reason: Range = Maximum observation − Minimum observation.
Correct Option: (c) Range

(v) The mean of the first 5 natural numbers is:

  • (a) 2.5
  • (b) 3
  • (c) 3.5
  • (d) 5
Step-by-step Solution:
First 5 natural numbers: 1, 2, 3, 4, 5.
Mean = (1 + 2 + 3 + 4 + 5)/5 = 15/5 = 3.
Correct Option: (b) 3

Q.1. (B) Short Answer Questions

(a) Find the mode of the following numbers: 12, 14, 12, 16, 15, 13, 14, 18, 14.

Frequencies:
• 12 occurs 2 times.
• 13 occurs 1 time.
• 14 occurs 3 times.
• 15 occurs 1 time; 16 occurs 1 time; 18 occurs 1 time.
Since 14 has the highest frequency (3 times), Mode = 14.
Ans: 14

(b) If the mean of 5 observations is 20, what is the sum of these observations?

Sum of observations = Mean × Number of observations = 20 × 5 = 100.
Ans: 100

(c) State the formula for finding the median when the number of observations (n) is odd.

Ans: Median = Value of the (n + 1)/2th observation when data is arranged in ascending or descending order.

(d) What is the range of the numbers: 23, 35, 12, 40, 56, 18, 29?

Highest value = 56; Lowest value = 12.
Range = 56 − 12 = 44.
Ans: 44

Q.2. Marks scored by 10 students in a mathematics test out of 50 are: 28, 35, 40, 35, 42, 38, 35, 45, 40, 32. Find the Mean, Median, and Mode

1. Calculation of Mean:
Sum = 28 + 35 + 40 + 35 + 42 + 38 + 35 + 45 + 40 + 32 = 370.
Total count = 10.
Mean = 370/10 = 37.

2. Calculation of Median:
Arranging marks in ascending order:
28, 32, 35, 35, 35, 38, 40, 40, 42, 45.
Since n = 10 (even), median is the average of 5th and 6th terms:
• 5th term = 35
• 6th term = 38
Median = (35 + 38)/2 = 73/2 = 36.5.

3. Calculation of Mode:
The mark 35 appears 3 times (highest frequency).
Mode = 35.

Ans: Mean = 37 | Median = 36.5 | Mode = 35

🔥 Higher Order Thinking Skills (HOTS)

HOTS Q1: The mean weight of a group of 20 students is 45 kg. If the weight of their teacher is included, the mean weight increases by 1 kg. Find the weight of the teacher.

Step 1: Total weight of 20 students:
Sumstudents = 20 × 45 = 900 kg.

Step 2: Total weight with teacher included (21 persons):
New Mean = 45 + 1 = 46 kg.
Total count = 21.
Sumtotal = 21 × 46 = 966 kg.

Step 3: Find teacher’s weight:
Weight of Teacher = 966 − 900 = 66 kg.
Ans: 66 kg

HOTS Q2: The mean of 10 observations is 25. If each observation is increased by 5, what will be the new mean? Prove mathematically.

Original sum = 10 × 25 = 250.
When each of the 10 observations is increased by 5, total increase = 10 × 5 = 50.
New Sum = 250 + 50 = 300.
New Mean = 300/10 = 30.
Property Proved: If a constant ‘k’ is added to every observation, the mean also increases by ‘k’ (25 + 5 = 30).
Ans: 30

🌱 Value Based Questions (VBQ)

VBQ: A school environment club conducts a survey on water consumption in 5 residential blocks. The daily water wastage recorded (in litres) is: 120, 150, 100, 180, 200.

(a) Find the average (mean) daily water wastage across the blocks.

Mean = (120 + 150 + 100 + 180 + 200)/5 = 750/5 = 150 litres.

(b) What value do students promote by highlighting this statistical data?

Core Values Depicted: Resource conservation, water preservation, ecological civic duty, and evidence-based awareness to stop resource wastage.
Ans: (a) 150 litres | (b) Conservation of Water & Social Awareness

📚 DAV Class 7 Maths Chapter 12: Data Handling – Complete Solutions Index

Worksheet / SectionCore Statistical MeasuresSolution Link
Worksheet 1Arithmetic Mean & Range CalculationsView Worksheet 1 →
Worksheet 2Median of Odd & Even Data SetsView Worksheet 2 →
Worksheet 3Mode of Raw & Frequency DataView Worksheet 3 →
Worksheet 4Bar Graphs, Double Bar Graphs & ScalesView Worksheet 4 →
Brain Teasers, HOTS & VBQsComprehensive Review, Weight Changes & ProofsCurrent Page
💬 🌟 Helping a friend? Share these answers:

Leave a Reply

✅ Link copied to clipboard!
📚 Share with Classmates
WhatsApp

📑 Chapter Navigation Directory

Add as a preferred source on Google
See ncertbookspdf.com first in Google Search