Are you looking for DAV Maths Solutions for class 8 then you are in right place, we have discussed the solution of the Secondary Mathematics book which is followed in all DAV School. Solutions are given below with proper Explanation please bookmark our website for the further update !! All the Best !!
DAV Class 8 Maths Chapter 1: all worksheets All Class 8 Maths chapters β
DAV SOLUTIONS CLASS 8 Secondary Mathematics Unit 1 Worksheet 2
Find the square root of the following 1. 16 2. 49 3. 64 4. 100 5. 169 6.81 7.256 8.144
Question1 :β16Β
16 – 1 = 15 (ii) 15 – 3 = 12 (iii) 12 – 5 = 7 (iv) 7 – 7 = 0
We have subtracted the successive odd numbers from 16 and obtained 0 in the forth
step. 16 = 4
Question2: β49
(1) 49 – 1 = 48 (ii) 48 – 3 = 45 (ΓΌl) 45 – 5 = 40 (iv) 40 – 7 = 33
(v) 33 – 9 = 24 (vi) 24 – 11 = 13 (vii) 13 – 13 = 0
We have subtracted the successive odd numbers from 49 and obtained 0 in the seventh
stepβ¦ β49= 7
Question3: β64
(1) 64 – 1 = 63 (ii) 63 -3 = 60 (iii) 60 – 5 = 55 (iv) 55 – 7 = 48
(V) 48 – 9 = 39 (vi) 39 – 11 = 28 (vii) 28 – 13 = 15 (viii) 15 – 15 = 0
We have subtracted the successive odd numbers from 64 and obtained 0 in the eighth
step. V64 = 8
Question4: β100
(1) 100 – 1 = 99 (il) 99 – 3 = 96 (iii) 96 – 5 = 91 (iv) 91 – 7 = 84
(V) 84 – 9 = 75 (vi) 75 – 11 = 64 (vii) 64 – 13 = 51 (viii) 51 – 15 = 36
(ix) 36 – 17 = 19 (x) 19 – 19 = 0
We have subtracted the successive odd numbers from 100 and obtained 0 in the tenth
step.
β100=10
Question 5: β169
(1) 169 -1 = 168 (ii) 168-3 = 165 (iii) 165 – 5 = 160 (iv) 160 – 7 = 153
(V) 153 – 9 = 144 (vi) 144 – 11 = 133 (vii) 133 – 13 = 120 (viit) 120 – 15 = 105
(ix) 105 – 17 = 88 (x) 88 – 19 = 69 (x1) 69 – 21 = 48 (xii) 48 – 23 = 25
(xiii) 25 – 25 = 0
We have subtracted successive odd numbers from 169 and obtained 0 in the thirteenth
step.
β169 = 13
Question6: β81
(1) 81 – 1 = 80 (ii) 80 – 3 = 77 (iii) 77 – 5 = 72 (iv) 72 – 7 = 65
(v) 65 – 9 = 56 (vi) 56 – 11 = 45 (vii) 45 – 13 = 32 (viii) 32 – 15 = 17
(ix) 17 – 17 = 0
We have subtracted successive odd natural numbers from 81 and obtained 0 in the ninth
step.
..
β81 = 9.
Question7: β256
(1) 256 – 1 = 255 (ii) 255-3 = 252 (iii) 252 – 5 = 247 (iv) 247 – 7 = 240
(v) 240 – 9 = 231 (vi) 231 – 11 = 220 (vii) 220 – 13 = 207 (viii) 207 – 15 = 192
(ix) 192 – 17 = 175 (x) 175 – 19 = 156 (xi) 156 – 13 = 135 (xii) 135 – 15 = 112
(xiii) 112 – 25 = 87 (xiv) 87 – 27 = 60 (xv) 60 – 29 = 31 (xvi) 31 – 31 = 0
We have subtracted successive odd natural numbers from 256 and obtained 0 in the
sixteenth step.
..
β256 = 16.
Question 8 : β144
144 – 1 = 143 2. 143 -3 = 140 3. 140 – 5 = 135 4. 135 – 7 = 128
128 – 9 = 119 6. 119 – 11 = 108 7. 108 – 13 = 95 8. 95 – 15 = 80
80 – 17 = 63 10. 63 – 19 = 44 11. 44 – 21 = 23 12. 23 – 23 = 0
We have subtracted successive odd natural numbers from 144 and obtained 0 in the
twelfth step.
β144 = 12.
Nice ππ»