- (a) $4text{ m} = 4 times 100 = mathbf{400text{ cm}}$
- (b) $6text{ m } 25text{ cm} = (6 times 100) + 25 = 600 + 25 = mathbf{625text{ cm}}$
- (c) $9text{ m } 8text{ cm} = (9 times 100) + 8 = 900 + 8 = mathbf{908text{ cm}}$
- (d) $15text{ m } 50text{ cm} = 1500 + 50 = mathbf{1550text{ cm}}$
2. Convert into Meters (m): Multiply the number of kilometers by 1,000 and add the meters.
- (a) $5text{ km} = 5 times 1000 = mathbf{5000text{ m}}$
- (b) $8text{ km } 350text{ m} = (8 times 1000) + 350 = 8000 + 350 = mathbf{8350text{ m}}$
- (c) $3text{ km } 45text{ m} = 3000 + 45 = mathbf{3045text{ m}}$
- (d) $7text{ km } 5text{ m} = 7000 + 5 = mathbf{7005text{ m}}$
Worksheet 2: Addition and Subtraction of Length
| Addition Working | Subtraction Working |
|---|---|
|
Add: $24text{ m } 45text{ cm} + 18text{ m } 75text{ cm}$ m cm (1) (1) 24 45 + 18 75 ————- 43 20 Sum = 43 m 20 cm |
Subtract: $45text{ m } 20text{ cm} – 18text{ m } 65text{ cm}$ m cm (44) (120) 45 20 – 18 65 ————- 26 55 Difference = 26 m 55 cm |
Worksheet 3: Word Problems on Length (With Statements)
Problem 1: A cloth merchant sold $28text{ m } 50text{ cm}$ of cotton cloth and $15text{ m } 75text{ cm}$ of silk cloth. What is the total length of cloth sold?
Solution:
Cotton cloth sold = $28text{ m } 50text{ cm}$
Silk cloth sold = $15text{ m } 75text{ cm}$
Total cloth sold = $28text{ m } 50text{ cm} + 15text{ m } 75text{ cm}$
m cm
28 50
+ 15 75
————-
44 25
Answer: The total length of cloth sold is 44 m 25 cm.
Problem 2: A roll of electric wire measured $85text{ m } 40text{ cm}$. An electrician cut off $32text{ m } 65text{ cm}$ for house wiring. Find the length of wire remaining in the roll.
Solution:
Total wire length = $85text{ m } 40text{ cm}$
Wire cut off = $32text{ m } 65text{ cm}$
Remaining wire = $85text{ m } 40text{ cm} – 32text{ m } 65text{ cm}$
m cm
84 140
– 32 65
————-
52 75
Answer: 52 m 75 cm of wire is left in the roll.
Quick Navigation Links:
DAV Board Class 3 Mathematics (Primary Mathematics) | 100% Authentic Textbook Solutions
DAV Class 3 Maths Unit 8 Solutions Length
Get complete, step-by-step textbook solutions for DAV Class 3 Primary Mathematics Unit 8: Length. This unit covers standard units of length (centimeter cm, meter m, kilometer km), unit conversions ($text{m to cm}$ and $text{km to m}$), column addition and subtraction of lengths with regrouping, and real-life measurement word problems strictly aligned with the DAV CMC syllabus.
| Class | Subject | Textbook | Unit Number & Title | Key Mathematical Concepts |
|---|---|---|---|---|
| Class 3 | Mathematics | Primary Mathematics | Unit 8: Length | Standard units (cm, m, km), conversions, addition & subtraction of length, word problems |
Worksheet 1: Standard Units & Conversions
Standard Conversion Formulas:
$$mathbf{1 text{ meter (m)} = 100 text{ centimeters (cm)}}$$
$$mathbf{1 text{ kilometer (km)} = 1,000 text{ meters (m)}}$$
1. Convert into Centimeters (cm): Multiply the number of meters by 100 and add the centimeters.
- (a) $4text{ m} = 4 times 100 = mathbf{400text{ cm}}$
- (b) $6text{ m } 25text{ cm} = (6 times 100) + 25 = 600 + 25 = mathbf{625text{ cm}}$
- (c) $9text{ m } 8text{ cm} = (9 times 100) + 8 = 900 + 8 = mathbf{908text{ cm}}$
- (d) $15text{ m } 50text{ cm} = 1500 + 50 = mathbf{1550text{ cm}}$
2. Convert into Meters (m): Multiply the number of kilometers by 1,000 and add the meters.
- (a) $5text{ km} = 5 times 1000 = mathbf{5000text{ m}}$
- (b) $8text{ km } 350text{ m} = (8 times 1000) + 350 = 8000 + 350 = mathbf{8350text{ m}}$
- (c) $3text{ km } 45text{ m} = 3000 + 45 = mathbf{3045text{ m}}$
- (d) $7text{ km } 5text{ m} = 7000 + 5 = mathbf{7005text{ m}}$
Worksheet 2: Addition and Subtraction of Length
| Addition Working | Subtraction Working |
|---|---|
|
Add: $24text{ m } 45text{ cm} + 18text{ m } 75text{ cm}$ m cm (1) (1) 24 45 + 18 75 ————- 43 20 Sum = 43 m 20 cm |
Subtract: $45text{ m } 20text{ cm} – 18text{ m } 65text{ cm}$ m cm (44) (120) 45 20 – 18 65 ————- 26 55 Difference = 26 m 55 cm |
Worksheet 3: Word Problems on Length (With Statements)
Problem 1: A cloth merchant sold $28text{ m } 50text{ cm}$ of cotton cloth and $15text{ m } 75text{ cm}$ of silk cloth. What is the total length of cloth sold?
Solution:
Cotton cloth sold = $28text{ m } 50text{ cm}$
Silk cloth sold = $15text{ m } 75text{ cm}$
Total cloth sold = $28text{ m } 50text{ cm} + 15text{ m } 75text{ cm}$
m cm
28 50
+ 15 75
————-
44 25
Answer: The total length of cloth sold is 44 m 25 cm.
Problem 2: A roll of electric wire measured $85text{ m } 40text{ cm}$. An electrician cut off $32text{ m } 65text{ cm}$ for house wiring. Find the length of wire remaining in the roll.
Solution:
Total wire length = $85text{ m } 40text{ cm}$
Wire cut off = $32text{ m } 65text{ cm}$
Remaining wire = $85text{ m } 40text{ cm} – 32text{ m } 65text{ cm}$
m cm
84 140
– 32 65
————-
52 75
Answer: 52 m 75 cm of wire is left in the roll.
Quick Navigation Links: