NCERT Solutions, Class 9 Maths Chapter 10 Circles: Exercise 10.5, answered for the NCERT Class 9 textbook.
Exercise 10.5 Class 9 Maths Chapter 10 Circles
1. In Fig. 10.36, A,B and C are three points on a circle with centre O such that тИа BOC = 30┬░ and тИаAOB = 60┬░. If D is a point on the circle other than the arc ABC, find тИаADC.


2. A chord of a circle is equal to the radius of the circle. Find the angle subtended by the chord at a point on the minor arc and also at a point on the major arc.

3. In Fig. 10.37, тИа PQR = 100┬░, where P, Q and R are points on a circle with centre O. Find тИа OPR.


4. In Fig. 10.38, тИа ABC = 69┬░, тИа ACB = 31┬░, find тИа BDC.


5. In Fig. 10.39, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that тИа BEC = 130┬░ and тИа ECD = 20┬░. Find тИа BAC.


6. ABCD is a cyclic quadrilateral whose diagonals intersect at a point E. If тИа DBC = 70┬░, тИа BAC is 30┬░, find тИа BCD. Further, if AB = BC, find тИа ECD.

7. If diagonals of a cyclic quadrilateral are diameters of the circle through the vertices of the quadrilateral, prove that it is a rectangle.

8. If the non-parallel sides of a trapezium are equal, prove that it is cyclic.

9. Two circles intersect at two points B and C. Through B, two line segments ABD and PBQ are drawn to intersect the circles at A, D and P, Q respectively (see Fig. 10.40). Prove that тИаACP = тИаQCD.


10. If circles are drawn taking two sides of a triangle as diameters, prove that the point of intersection of these circles lie on the third side.

11. ABC and ADC are two right triangles with common hypotenuse AC. Prove that тИа CAD = тИаCBD.

12. Prove that a cyclic parallelogram is a rectangle.
