NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles

NCERT Solutions, Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles: Exercise 9.3, answered for the NCERT Class 9 textbook.

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Exercise 9.3 Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles

1. In Fig.9.23, E is any point on median AD of a тИЖ ABC. Show that ar (ABE) = ar (ACE).

NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles
NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles

2. In a triangle ABC, E is the mid-point of median AD. Show that ar (BED) = 1/2 ar(ABC).

NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles

3. Show that the diagonals of a parallelogram divide it into four triangles of equal area.

NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles

4. In Fig. 9.24, ABC and ABD are two triangles on the same base AB. If line- segment CD is bisected by AB at O, show that ar(ABC) = ar (ABD).

NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles
NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles

5. D, E and F are respectively the mid-points of the sides BC, CA and AB of a тИЖ ABC. Show that
(i) BDEF is a parallelogram. (ii) ar (DEF) = 1/4ar (ABC) (iii) ar (BDEF) = 1/2ar (ABC)

NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles
NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles

6. In Fig. 9.25, diagonals AC and BD of quadrilateral ABCD intersect at O such that OB = OD. If AB = CD, then show that:
(i) ar (DOC) = ar (AOB)
(ii) ar (DCB) = ar (ACB)
(iii) DA || CB or ABCD is a parallelogram.
[Hint: From D and B, draw perpendiculars to AC.]

NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles
NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles
NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles

7. D and E are points on sides AB and AC respectively of тИЖ ABC such that ar (DBC) = ar (EBC). Prove that DE || BC.

NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles

8. XY is a line parallel to side BC of a triangle ABC. If BE || AC and CF || AB meet XY at E and F respectively, show that ar (ABE) = ar (ACF)

NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles

9. The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q and then parallelogram PBQR is completed (see Fig. 9.26). Show that ar (ABCD) = ar (PBQR).
[Hint : Join AC and PQ. Now compare ar (ACQ) and ar (APQ).]

NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles
NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles

10. Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at O. Prove that ar (AOD) = ar (BOC).

NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles

11. In Fig. 9.27, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that
(i) ar (ACB) = ar (ACF)
(ii) ar (AEDF) = ar (ABCDE)

NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles
NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles

12. A villager Itwaari has a plot of land of the shape of a quadrilateral. The Gram Panchayat of the village decided to take over some portion of his plot from one of the corners to construct a Health Centre. Itwaari agrees to the above proposal with the condition that he should be given equal amount of land in lieu of his land adjoining his plot so as to form a triangular plot. Explain how this proposal will be implemented.

NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles

13. ABCD is a trapezium with AB || DC. A line parallel to AC intersects AB at X and BC
at Y. Prove that ar (ADX) = ar (ACY). [Hint: Join CX.]

NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles

14. In Fig.9.28, AP || BQ || CR. Prove that ar (AQC) = ar (PBR).

NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles
NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles

15. Diagonals AC and BD of a quadrilateral ABCD intersect at O in such a way that ar (AOD) = ar (BOC). Prove that ABCD is a trapezium.

NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles

16. In Fig.9.29, ar (DRC) = ar (DPC) and ar (BDP) = ar (ARC). Show that both the quadrilaterals ABCD and DCPR are trapeziums.

NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles
NCERT Solutions | Class 9 Maths Chapter 9 Areas of Parallelograms and Triangles
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