**NCERT Class 9 Maths Solutions PDF**: In this post, we have discussed the solution of the Maths class 9 book which is followed in all CBSE schools. Solutions are given below with proper Explanation and utmost care has been taken to ensure that the solutions are correct. Answers provided will not only help in completing all the assignments but also help students in clearing their concepts. Students can download the solutions by printing the chapters by using the command Ctrl+P in google chrome and saving it in PDF format. All the best !! Please support us by sharing this website with your school friends.

**Exercise 7.1 Class 9 Maths Chapter 7 Triangles**

**1. In quadrilateral ACBD, AC = AD and AB bisect ∠ A (see Fig. 7.16). Show that ∆ ABC ≅ ∆ ABD. What can you say about BC and BD?**

**2. ABCD is a quadrilateral in which AD = BC and ∠ DAB = ∠ CBA (see Fig. 7.17). Prove that(i) ∆ ABD ≅ ∆ BAC(ii) BD = AC(iii) ∠ ABD = ∠ BAC.**

**3. AD and BC are equal perpendiculars to a line segment AB (see Fig. 7.18). Show that CD bisects AB.**

**4. l and m are two parallel lines intersected by another pair of parallel lines p and q (see Fig. 7.19). Show that ∆ ABC ≅ ∆ CDA.**

**5. Line l is the bisector of an angle ∠ A and B is any point on l. BP and BQ are perpendiculars from B to the arms of ∠ A (see Fig. 7.20). Show that:(i) ∆ APB ≅ ∆ AQB(ii) BP = BQ or B is equidistant from the arms of ∠ A.**

**6. In Fig. 7.21, AC = AE, AB = AD and ∠ BAD = ∠ EAC. Show that BC = DE.**

**7. AB is a line segment and P is its mid-point. D and E are points on the same side of AB such that ∠ BAD = ∠ ABE and ∠ EPA = ∠ DPB (see Fig. 7.22). Show that(i) ∆ DAP ≅ ∆ EBP(ii) AD = BE**

**8. In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM = CM. Point D is joined to point B (see Fig. 7.23). Show that:(i) ∆ AMC ≅ ∆ BMD(ii) ∠ DBC is a right angle.(iii) ∆ DBC ≅ ∆ ACB(iv) CM = 1/2AB**