Simplification Questions for Class 6 with Answers: Practise solved Class 6 BODMAS and bracket simplification questions—including vinculum (bar) brackets, ‘of’ operations, round/curly/square brackets, and practice problems with answers.
BODMAS Rule Table for Class 6 Simplification
In Class 6 Mathematics, expressions often combine vinculum bars, nested brackets, and the word ‘of’. Follow this exact order:
| Rule Letter | Operation | Symbols & Priority |
|---|---|---|
| V | Vinculum (Bar) | Horizontal bar ‾ over numbers (solve first) |
| B | Brackets | Small ( ), then Curly { }, then Square [ ] |
| O | Of / Order | ‘of’ (means multiply before ÷), exponents & roots |
| D | Division | ÷ or / |
| M | Multiplication | × or * |
| A | Addition | + |
| S | Subtraction | − |
11 Solved Simplification Questions for Class 6 with Step-by-Step Answers
1. Simplify: 9 ÷ 3 + 2 × 7 − 16
Solution:
= 3 + 2 × 7 − 16 (As per BODMAS rule, perform division first: 9 ÷ 3 = 3)
= 3 + 14 − 16 (Perform multiplication: 2 × 7 = 14)
= 17 − 16 = 1
2. Simplify: (3 × 4 − 8) + (44 ÷ 11 + 6)
Solution:
= (12 − 8) + (4 + 6) (Inside first bracket multiply 3 × 4; inside second divide 44 ÷ 11)
= 4 + 10
= 14
3. Simplify: 3 × (2 × 5 − 6) + 8 − 15 ÷ 3
Solution:
= 3 × (10 − 6) + 8 − 15 ÷ 3 (Multiply inside bracket: 2 × 5 = 10)
= 3 × 4 + 8 − 5 (Remove bracket and divide 15 ÷ 3 = 5)
= 12 + 8 − 5 = 20 − 5 = 15
4. Simplify: (9 + 12) ÷ 7 + 36 ÷ 2 of 3
Solution:
= 21 ÷ 7 + 36 ÷ 2 of 3 (Solve bracket first: 9 + 12 = 21)
= 21 ÷ 7 + 36 ÷ 6 (Solve ‘2 of 3’ = 2 × 3 = 6 before division)
= 3 + 6 = 9
5. Simplify: (2 of 4 + 6) ÷ 2 − 35 ÷ 7
Solution:
= (8 + 6) ÷ 2 − 35 ÷ 7 (Solve ‘2 of 4’ = 8 inside bracket)
= 14 ÷ 2 − 35 ÷ 7 (Remove bracket)
= 7 − 5 (Perform both divisions)
= 2
6. Simplify: 16 + [7 + {(3 + 7) − 5̅−̅3̅}]
Solution:
= 16 + [7 + {(3 + 7) − 2}] (Solve vinculum bar first: 5 − 3 = 2)
= 16 + [7 + {10 − 2}] (Remove small bracket: 3 + 7 = 10)
= 16 + [7 + 8] (Remove curly bracket: 10 − 2 = 8)
= 16 + 15 = 31
7. Simplify: 13 + 6{10 − 6 ÷ 3}
Solution:
= 13 + 6{10 − 2} (Divide inside curly bracket: 6 ÷ 3 = 2)
= 13 + 6 × 8 (Remove curly bracket: 10 − 2 = 8)
= 13 + 48 = 61
8. Simplify: 12 + [7 − (4 ÷ 2) − 3̅−̅1̅]
Solution:
= 12 + [7 − (4 ÷ 2) − 2] (Solve vinculum bar first: 3 − 1 = 2)
= 12 + [7 − 2 − 2] (Remove small bracket: 4 ÷ 2 = 2)
= 12 + 3 = 15
9. Simplify: 36 − [18 − {14 − (15 − 4 ÷ 2 × 2)}]
Solution:
= 36 − [18 − {14 − (15 − 2 × 2)}] (Divide inside small bracket: 4 ÷ 2 = 2)
= 36 − [18 − {14 − (15 − 4)}] (Multiply inside small bracket: 2 × 2 = 4)
= 36 − [18 − {14 − 11}] (Remove small bracket)
= 36 − [18 − 3] (Remove curly bracket)
= 36 − 15 = 21
10. Simplify: 85 + 6{10 + 27 ÷ 3}
Solution:
= 85 + 6{10 + 9} (Divide inside curly bracket: 27 ÷ 3 = 9)
= 85 + 6 × 19
= 85 + 114 = 199
11. Objective Question: 8 + 4 ÷ 2 × 5 = ? (a) 30 (b) 50 (c) 18 (d) none of these
Solution: 8 + (4 ÷ 2) × 5 = 8 + 2 × 5 = 8 + 10 = 18 (Option c).
Extra Practice Simplification Questions for Class 6 (With Answers)
Try these 5 bracket simplification questions on your own, then check the solved answers below:
- Simplify: (12 + 18) × (15 − 9) — Answer: 30 × 6 = 180
- Simplify: (8 × 7) + (6 × 5) + (4 × 3) — Answer: 56 + 30 + 12 = 98
- Simplify: (12 × 8) − (15 + 9) — Answer: 96 − 24 = 72
- Simplify: (20 − 15) × (12 + 8) — Answer: 5 × 20 = 100
- Simplify: (18 × 9) + (6 × 4) − (12 + 8) — Answer: 162 + 24 − 20 = 166
Related Class 5 & Class 6 Maths Practice Resources
- NCERT Class 6 Maths Book (Ganita Prakash) PDF Download
- Simplification Questions for Class 5 with Answers
- BODMAS Questions for Class 5 with Answers
- DMAS Questions for Class 5 with Answers
Frequently Asked Questions on Class 6 Simplification
How do you solve 'of' in Class 6 simplification questions?
In BODMAS, 'of' stands for multiplication that must be carried out right after brackets and before division. For example, in 36 ÷ 2 of 3, first multiply 2 × 3 = 6, and then divide 36 ÷ 6 to get the correct answer 6.
What is the bar or vinculum in Class 6 BODMAS questions?
A vinculum is a horizontal line drawn above a group of numbers, such as 5 − 3 with a bar on top. You must simplify the expression directly underneath the bar before solving round (), curly {}, or square [] brackets.
What is the difference between BODMAS and PEDMAS?
BODMAS (Brackets, Order/Of, Division, Multiplication, Addition, Subtraction) is the standard term taught in Indian schools (CBSE/NCERT), while PEDMAS (Parentheses, Exponents, Division, Multiplication, Addition, Subtraction) is used in the United States.