Simplification Questions for Class 6 with Answers (BODMAS & Brackets)

Simplification Questions for Class 6 with Answers: Practise solved Class 6 BODMAS and bracket simplification questionsβ€”including vinculum (bar) brackets, ‘of’ operations, round/curly/square brackets, and practice problems with answers.

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Simplification Questions for Class 6 with Answers

BODMAS Rule Table for Class 6 Simplification

In Class 6 Mathematics, expressions often combine vinculum bars, nested brackets, and the word ‘of’. Follow this exact order:

Rule LetterOperationSymbols & Priority
VVinculum (Bar)Horizontal bar β€Ύ over numbers (solve first)
BBracketsSmall ( ), then Curly { }, then Square [ ]
OOf / Order‘of’ (means multiply before Γ·), exponents & roots
DDivisionΓ· or /
MMultiplicationΓ— or *
AAddition+
SSubtractionβˆ’

11 Solved Simplification Questions for Class 6 with Step-by-Step Answers

1. Simplify: 9 Γ· 3 + 2 Γ— 7 βˆ’ 16
Solution:
= 3 + 2 Γ— 7 βˆ’ 16  (As per BODMAS rule, perform division first: 9 Γ· 3 = 3)
= 3 + 14 βˆ’ 16  (Perform multiplication: 2 Γ— 7 = 14)
= 17 βˆ’ 16 = 1


2. Simplify: (3 Γ— 4 βˆ’ 8) + (44 Γ· 11 + 6)
Solution:
= (12 βˆ’ 8) + (4 + 6)  (Inside first bracket multiply 3 Γ— 4; inside second divide 44 Γ· 11)
= 4 + 10
= 14


3. Simplify: 3 Γ— (2 Γ— 5 βˆ’ 6) + 8 βˆ’ 15 Γ· 3
Solution:
= 3 Γ— (10 βˆ’ 6) + 8 βˆ’ 15 Γ· 3  (Multiply inside bracket: 2 Γ— 5 = 10)
= 3 Γ— 4 + 8 βˆ’ 5  (Remove bracket and divide 15 Γ· 3 = 5)
= 12 + 8 βˆ’ 5 = 20 βˆ’ 5 = 15


4. Simplify: (9 + 12) Γ· 7 + 36 Γ· 2 of 3
Solution:
= 21 Γ· 7 + 36 Γ· 2 of 3  (Solve bracket first: 9 + 12 = 21)
= 21 Γ· 7 + 36 Γ· 6  (Solve ‘2 of 3’ = 2 Γ— 3 = 6 before division)
= 3 + 6 = 9


5. Simplify: (2 of 4 + 6) Γ· 2 βˆ’ 35 Γ· 7
Solution:
= (8 + 6) Γ· 2 βˆ’ 35 Γ· 7  (Solve ‘2 of 4’ = 8 inside bracket)
= 14 Γ· 2 βˆ’ 35 Γ· 7  (Remove bracket)
= 7 βˆ’ 5  (Perform both divisions)
= 2


6. Simplify: 16 + [7 + {(3 + 7) βˆ’ 5Μ…βˆ’Μ…3Μ…}]
Solution:
= 16 + [7 + {(3 + 7) βˆ’ 2}]  (Solve vinculum bar first: 5 βˆ’ 3 = 2)
= 16 + [7 + {10 βˆ’ 2}]  (Remove small bracket: 3 + 7 = 10)
= 16 + [7 + 8]  (Remove curly bracket: 10 βˆ’ 2 = 8)
= 16 + 15 = 31


7. Simplify: 13 + 6{10 βˆ’ 6 Γ· 3}
Solution:
= 13 + 6{10 βˆ’ 2}  (Divide inside curly bracket: 6 Γ· 3 = 2)
= 13 + 6 Γ— 8  (Remove curly bracket: 10 βˆ’ 2 = 8)
= 13 + 48 = 61


8. Simplify: 12 + [7 βˆ’ (4 Γ· 2) βˆ’ 3Μ…βˆ’Μ…1Μ…]
Solution:
= 12 + [7 βˆ’ (4 Γ· 2) βˆ’ 2]  (Solve vinculum bar first: 3 βˆ’ 1 = 2)
= 12 + [7 βˆ’ 2 βˆ’ 2]  (Remove small bracket: 4 Γ· 2 = 2)
= 12 + 3 = 15


9. Simplify: 36 βˆ’ [18 βˆ’ {14 βˆ’ (15 βˆ’ 4 Γ· 2 Γ— 2)}]
Solution:
= 36 βˆ’ [18 βˆ’ {14 βˆ’ (15 βˆ’ 2 Γ— 2)}]  (Divide inside small bracket: 4 Γ· 2 = 2)
= 36 βˆ’ [18 βˆ’ {14 βˆ’ (15 βˆ’ 4)}]  (Multiply inside small bracket: 2 Γ— 2 = 4)
= 36 βˆ’ [18 βˆ’ {14 βˆ’ 11}]  (Remove small bracket)
= 36 βˆ’ [18 βˆ’ 3]  (Remove curly bracket)
= 36 βˆ’ 15 = 21


10. Simplify: 85 + 6{10 + 27 Γ· 3}
Solution:
= 85 + 6{10 + 9}  (Divide inside curly bracket: 27 Γ· 3 = 9)
= 85 + 6 Γ— 19
= 85 + 114 = 199


11. Objective Question: 8 + 4 Γ· 2 Γ— 5 = ?   (a) 30   (b) 50   (c) 18   (d) none of these
Solution: 8 + (4 Γ· 2) Γ— 5 = 8 + 2 Γ— 5 = 8 + 10 = 18 (Option c).


Extra Practice Simplification Questions for Class 6 (With Answers)

Try these 5 bracket simplification questions on your own, then check the solved answers below:

  1. Simplify: (12 + 18) Γ— (15 βˆ’ 9)  β€” Answer: 30 Γ— 6 = 180
  2. Simplify: (8 Γ— 7) + (6 Γ— 5) + (4 Γ— 3)  β€” Answer: 56 + 30 + 12 = 98
  3. Simplify: (12 Γ— 8) βˆ’ (15 + 9)  β€” Answer: 96 βˆ’ 24 = 72
  4. Simplify: (20 βˆ’ 15) Γ— (12 + 8)  β€” Answer: 5 Γ— 20 = 100
  5. Simplify: (18 Γ— 9) + (6 Γ— 4) βˆ’ (12 + 8)  β€” Answer: 162 + 24 βˆ’ 20 = 166

Related Class 5 & Class 6 Maths Practice Resources

Frequently Asked Questions on Class 6 Simplification

How do you solve 'of' in Class 6 simplification questions?

In BODMAS, 'of' stands for multiplication that must be carried out right after brackets and before division. For example, in 36 Γ· 2 of 3, first multiply 2 Γ— 3 = 6, and then divide 36 Γ· 6 to get the correct answer 6.

What is the bar or vinculum in Class 6 BODMAS questions?

A vinculum is a horizontal line drawn above a group of numbers, such as 5 βˆ’ 3 with a bar on top. You must simplify the expression directly underneath the bar before solving round (), curly {}, or square [] brackets.

What is the difference between BODMAS and PEDMAS?

BODMAS (Brackets, Order/Of, Division, Multiplication, Addition, Subtraction) is the standard term taught in Indian schools (CBSE/NCERT), while PEDMAS (Parentheses, Exponents, Division, Multiplication, Addition, Subtraction) is used in the United States.

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