Simplification Questions for Class 6 with Answers: Practise solved Class 6 BODMAS and bracket simplification questionsβincluding vinculum (bar) brackets, ‘of’ operations, round/curly/square brackets, and practice problems with answers.

BODMAS Rule Table for Class 6 Simplification
In Class 6 Mathematics, expressions often combine vinculum bars, nested brackets, and the word ‘of’. Follow this exact order:
| Rule Letter | Operation | Symbols & Priority |
|---|---|---|
| V | Vinculum (Bar) | Horizontal bar βΎ over numbers (solve first) |
| B | Brackets | Small ( ), then Curly { }, then Square [ ] |
| O | Of / Order | ‘of’ (means multiply before Γ·), exponents & roots |
| D | Division | Γ· or / |
| M | Multiplication | Γ or * |
| A | Addition | + |
| S | Subtraction | β |
11 Solved Simplification Questions for Class 6 with Step-by-Step Answers
1. Simplify: 9 Γ· 3 + 2 Γ 7 β 16
Solution:
= 3 + 2 Γ 7 β 16 (As per BODMAS rule, perform division first: 9 Γ· 3 = 3)
= 3 + 14 β 16 (Perform multiplication: 2 Γ 7 = 14)
= 17 β 16 = 1
2. Simplify: (3 Γ 4 β 8) + (44 Γ· 11 + 6)
Solution:
= (12 β 8) + (4 + 6) (Inside first bracket multiply 3 Γ 4; inside second divide 44 Γ· 11)
= 4 + 10
= 14
3. Simplify: 3 Γ (2 Γ 5 β 6) + 8 β 15 Γ· 3
Solution:
= 3 Γ (10 β 6) + 8 β 15 Γ· 3 (Multiply inside bracket: 2 Γ 5 = 10)
= 3 Γ 4 + 8 β 5 (Remove bracket and divide 15 Γ· 3 = 5)
= 12 + 8 β 5 = 20 β 5 = 15
4. Simplify: (9 + 12) Γ· 7 + 36 Γ· 2 of 3
Solution:
= 21 Γ· 7 + 36 Γ· 2 of 3 (Solve bracket first: 9 + 12 = 21)
= 21 Γ· 7 + 36 Γ· 6 (Solve ‘2 of 3’ = 2 Γ 3 = 6 before division)
= 3 + 6 = 9
5. Simplify: (2 of 4 + 6) Γ· 2 β 35 Γ· 7
Solution:
= (8 + 6) Γ· 2 β 35 Γ· 7 (Solve ‘2 of 4’ = 8 inside bracket)
= 14 Γ· 2 β 35 Γ· 7 (Remove bracket)
= 7 β 5 (Perform both divisions)
= 2
6. Simplify: 16 + [7 + {(3 + 7) β 5Μ
βΜ
3Μ
}]
Solution:
= 16 + [7 + {(3 + 7) β 2}] (Solve vinculum bar first: 5 β 3 = 2)
= 16 + [7 + {10 β 2}] (Remove small bracket: 3 + 7 = 10)
= 16 + [7 + 8] (Remove curly bracket: 10 β 2 = 8)
= 16 + 15 = 31
7. Simplify: 13 + 6{10 β 6 Γ· 3}
Solution:
= 13 + 6{10 β 2} (Divide inside curly bracket: 6 Γ· 3 = 2)
= 13 + 6 Γ 8 (Remove curly bracket: 10 β 2 = 8)
= 13 + 48 = 61
8. Simplify: 12 + [7 β (4 Γ· 2) β 3Μ
βΜ
1Μ
]
Solution:
= 12 + [7 β (4 Γ· 2) β 2] (Solve vinculum bar first: 3 β 1 = 2)
= 12 + [7 β 2 β 2] (Remove small bracket: 4 Γ· 2 = 2)
= 12 + 3 = 15
9. Simplify: 36 β [18 β {14 β (15 β 4 Γ· 2 Γ 2)}]
Solution:
= 36 β [18 β {14 β (15 β 2 Γ 2)}] (Divide inside small bracket: 4 Γ· 2 = 2)
= 36 β [18 β {14 β (15 β 4)}] (Multiply inside small bracket: 2 Γ 2 = 4)
= 36 β [18 β {14 β 11}] (Remove small bracket)
= 36 β [18 β 3] (Remove curly bracket)
= 36 β 15 = 21
10. Simplify: 85 + 6{10 + 27 Γ· 3}
Solution:
= 85 + 6{10 + 9} (Divide inside curly bracket: 27 Γ· 3 = 9)
= 85 + 6 Γ 19
= 85 + 114 = 199
11. Objective Question: 8 + 4 Γ· 2 Γ 5 = ? (a) 30 (b) 50 (c) 18 (d) none of these
Solution: 8 + (4 Γ· 2) Γ 5 = 8 + 2 Γ 5 = 8 + 10 = 18 (Option c).
Extra Practice Simplification Questions for Class 6 (With Answers)
Try these 5 bracket simplification questions on your own, then check the solved answers below:
- Simplify: (12 + 18) Γ (15 β 9) β Answer: 30 Γ 6 = 180
- Simplify: (8 Γ 7) + (6 Γ 5) + (4 Γ 3) β Answer: 56 + 30 + 12 = 98
- Simplify: (12 Γ 8) β (15 + 9) β Answer: 96 β 24 = 72
- Simplify: (20 β 15) Γ (12 + 8) β Answer: 5 Γ 20 = 100
- Simplify: (18 Γ 9) + (6 Γ 4) β (12 + 8) β Answer: 162 + 24 β 20 = 166
Related Class 5 & Class 6 Maths Practice Resources
- NCERT Class 6 Maths Book (Ganita Prakash) PDF Download
- Simplification Questions for Class 5 with Answers
- BODMAS Questions for Class 5 with Answers
- DMAS Questions for Class 5 with Answers
Frequently Asked Questions on Class 6 Simplification
How do you solve 'of' in Class 6 simplification questions?
In BODMAS, 'of' stands for multiplication that must be carried out right after brackets and before division. For example, in 36 Γ· 2 of 3, first multiply 2 Γ 3 = 6, and then divide 36 Γ· 6 to get the correct answer 6.
What is the bar or vinculum in Class 6 BODMAS questions?
A vinculum is a horizontal line drawn above a group of numbers, such as 5 β 3 with a bar on top. You must simplify the expression directly underneath the bar before solving round (), curly {}, or square [] brackets.
What is the difference between BODMAS and PEDMAS?
BODMAS (Brackets, Order/Of, Division, Multiplication, Addition, Subtraction) is the standard term taught in Indian schools (CBSE/NCERT), while PEDMAS (Parentheses, Exponents, Division, Multiplication, Addition, Subtraction) is used in the United States.