Exercise 7.3 Class 9 Chapter 7 Maths Solutions Triangles: Exercise 7.3, answered for the NCERT Class 9 textbook.
Exercise 7.3 Class 9 Maths Chapter 7 Triangles
1. тИЖ ABC and тИЖ DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see Fig. 7.39). If AD is extended to intersect BC at P, show that
(i) тИЖ ABD тЙЕ тИЖ ACD
(ii) тИЖ ABPтЙЕ тИЖ ACP
(iii) AP bisects тИа A as well as тИа D.
(iv) AP is the perpendicular bisector of BC.



2. AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that
(i) AD bisects BC (ii) AD bisects тИа A.

3. Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of тИЖ PQR (see Fig. 7.40). Show that:
(i) тИЖ ABM тЙЕ тИЖ PQN
(ii) тИЖ ABC тЙЕ тИЖ PQR


4. BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule, prove that the triangle ABC is isosceles.

5. ABC is an isosceles triangle with AB = AC. Draw AP тКе BC to show that тИа B = тИа C.
