CG SCERT (Chhattisgarh Board) Class 8 Mathematics Solutions | 2026-27 Official Edition
Complete 100% textbook-grounded CG Board Class 8 Mathematics Chapter 16 Solutions: Figures (Two and Three Dimensional) (आकृतियाँ (द्विविमीय एवं त्रिविमीय)) in Bilingual Format (English & Hindi Medium).
V – E + F = 2 or F + V – E = 2
- V = Vertices
- E = Edges
- F = Faces
- Cuboid:
- English: V = 8, E = 12, F = 6 ⇒ V – E + F = 8 – 12 + 6 = 2
- Hindi: V = 8, E = 12, F = 6 ⇒ V – E + F = 8 – 12 + 6 = 2
- Cube:
- English: V = 8, E = 12, F = 6 ⇒ V – E + F = 8 – 12 + 6 = 2
- Hindi: V = 8, E = 12, F = 6 ⇒ V – E + F = 8 – 12 + 6 = 2
- Tetrahedron / Triangular Pyramid:
- English: V = 4, E = 6, F = 4 ⇒ V – E + F = 4 – 6 + 4 = 2
- Hindi: V = 4, E = 6, F = 4 ⇒ V – E + F = 4 – 6 + 4 = 2
- Square Pyramid:
- English: V = 5, E = 8, F = 5 ⇒ V – E + F = 5 – 8 + 5 = 2
- Hindi: V = 5, E = 8, F = 5 ⇒ V – E + F = 5 – 8 + 5 = 2
- Triangular Prism:
- English: V = 6, E = 9, F = 5 ⇒ V – E + F = 6 – 9 + 5 = 2
- Hindi: V = 6, E = 9, F = 5 ⇒ V – E + F = 6 – 9 + 5 = 2
Question 1
Construct prepare a cube with the help of…
3 सेमी के वर्ग की सहायता से घन…
📝 Question:
Construct (prepare) a cube with the help of a square of 3 cm.**
💡 Solution:
- Draw a square ABCD of side 3 cm.
- Draw another identical square EFGH of side 3 cm shifted slightly above and to the right.
- Join the corresponding vertices: AE, BF, CG, and DH.
- The resulting 3D figure with 6 identical square faces of side 3 cm is the required cube.
Question 2
Construct a cylinder of 5 cm length
5 सेमी लंबाई ऊँचाई के बेलन का निर्माण…
📝 Question:
Construct a cylinder of 5 cm length.**
💡 Solution:
- Draw two identical parallel ellipses (representing the top and bottom circular bases) separated by a vertical distance of 5 cm.
- Label the centers O1 and O2 such that O_1O2 = 5 cm.
- Join the endpoints of the parallel diameters A_1A2 and B_1B2 with straight vertical line segments.
- The resulting figure with two circular bases and one curved surface is the required cylinder of length 5 cm.
Question 3
Construct two triangles at a distance of 5…
अपनी कॉपी में त्रिभुजाकार हार्डबोर्ड की सहायता से…
📝 Question:
Construct two triangles at a distance of 5 cm in your notebook with the help of a triangular hardboard and construct a triangular prism with its help.**
💡 Solution:
- Draw a triangle △ ABC using the triangular board as an outline.
- At a parallel distance of 5 cm, draw an identical triangle △ A_1B_1C1.
- Join the corresponding vertices: AA1, BB1, and CC1 with straight line segments.
- The solid figure formed with 2 triangular faces and 3 rectangular faces is the required triangular prism.
Question 4
Construct a quadrilateral in your notebook
अपनी कॉपी में एक चतुर्भुज की रचना कीजिए।…
📝 Question:
Construct a quadrilateral in your notebook.**
💡 Solution:
- Draw a line segment AB of any suitable length using a ruler.
- From point B, draw a line segment BC at an angle.
- From point C, draw line segment CD.
- Join point D to point A to complete the closed 2D polygon ABCD having 4 sides, 4 angles, and 4 vertices.
Question 5
If there are 4 faces and 4 vertices…
यदि किसी बहुफलक में 4 फलक Faces और…
📝 Question:
If there are 4 faces and 4 vertices in a polyhedron, can you tell how many edges will be there in it?**
💡 Solution:
Given
- Number of Faces (F) = 4
- Number of Vertices (V) = 4
By Euler’s Formula for Polyhedra
V – E + F = 2
Substituting the given values
4 – E + 4 = 2
8 – E = 2 ⇒ E = 8 – 2 = 6
Therefore, the polyhedron has 6 edges (This figure is a Tetrahedron / Triangular Pyramid).