CG SCERT (Chhattisgarh Board) Class 8 Mathematics Solutions | 2026-27 Official Edition
Complete 100% textbook-grounded CG Board Class 8 Mathematics Chapter 10 Solutions: Polygon (बहुभुज) in Bilingual Format (English & Hindi Medium).
Choose the correct alternative answer a The two…
प्रत्येक प्रश्न के चार विकल्प दिए गए हैं।…
(i) a parallelogram (ii) quadrilateral (iii) rectangle (iv) trapezium**
(i) parallelogram (ii) trapezium (iii) rectangle (iv) rhombus
(i) 60°(ii) 120°(iii) 90°(iv) 180°
(i) 14 cm (ii) 28 cm (iii) 56 cm (iv) 60 cm
Fill in the blanks
रिक्त स्थानों की पूर्ति कीजिए वह चतुर्भुज जिसके…
(1) A quadrilateral where the diagonals are equal and intersect each other at right angle, is known as a ……………….**
- (2) The quadrilateral in which only one pair of opposite sides are parallel is known as an ……………….
- (3) If a polygon has 6 vertices, then the number of sides in the polygon would be ………
- (4) If the number of sides in a polygon is “n” then the number of diagonals that can be drawn from one of the vertices would be ……………….
The four vertices of a square piece of…
कागज के एक वर्गाकार टुकड़े के चारों शीर्षों…
Cutting off the 4 vertices (corners) of a square adds 4 new straight edge segments to the existing 4 sides, resulting in an 8-sided polygon called an Octagon.
The sides of a polygon are 8 in…
एक बहुभुज की 8 भुजाएँ हैं। इसके अंतःकोणों…
Sum of internal angles = (n – 2) × 180°.
Here n = 8.
Sum of internal angles = (8 – 2) × 180°= 6 × 180°= 1080° × 180°= 1080°)*
If one of the angles of a parallelogram…
यदि समान्तर चतुर्भुज का एक कोण 120है तो…
- Let the given angle be ∠ A = 120°.
- Opposite angle ∠ C = ∠ A = 120°(opposite angles of a parallelogram are equal).
- Adjacent angle ∠ B = 180°- 120°= 60°(adjacent angles are supplementary).
- Opposite angle ∠ D = ∠ B = 60°.
The remaining angles are 120°, 60°, 60°.
The adjacent sides of a parallelogram are in…
समान्तर चतुर्भुज की आसन्न भुजाएँ 3 4 के…
- Let the adjacent sides be 3x and 4x.
- Perimeter formula = 2 × (3x + 4x) = 14x.
- Given Perimeter = 84 cm.
14x = 84 ⇒ x = 84/14 = 6
- First side = 3 × 6 = 18 cm.
- Second side = 4 × 6 = 24 cm.
Which of these statements are not true Correct…
इनमें से कौनसे कथन सत्य नहीं हैं उन्हें…
- All squares are rhombus.
*True.
- The diagonals of a rectangle are equal.
*True.
- All rectangles are not parallelograms.
*False.
- Correction / : All rectangles are parallelograms.
- The diagonals of a parallelogram bisect each other at right angles.
*False.
- Correction / : The diagonals of a parallelogram bisect each other, but not necessarily at right angles.
- All squares are rectangles.
*True.
### *EXERCISE 10.2
Three angles of a quadrilateral are 80 110and…
किसी चतुर्भुज के तीन कोण क्रमशः 80 110तथा…
- Sum of all interior angles of a quadrilateral = 360°.
- Let fourth angle = x.
80°+ 110°+ 120°+ x = 360°310°+ x = 360°x = 360°- 310°= 50°
If three angles of any quadrilateral are equal…
यदि किसी चतुर्भुज के तीन कोण बराबर हों…
- Let each of the three equal angles = x.
x + x + x + 75°= 360°3x + 75°= 360°3x = 360°- 75°= 285°x = frac{285°{3} = 95°
Ratio of the adjacent angles of a parallelogram…
एक समान्तर चतुर्भुज के आसन्न कोणों का अनुपात…
- Let adjacent angles be 2x and 3x.
- Sum of adjacent angles of a parallelogram = 180°.
2x + 3x = 180° ⇒ 5x = 180° ⇒ x = 36°* First angle = 2 × 36°= 72°.
- Second angle = 3 × 36°= 108°.
- Opposite angles are equal, so the four angles are 72°, 108°, 72°, 108°.
One angle of a quadrilateral is a right…
किसी चतुर्भुज का एक कोण समकोण है तथा…
- Right angle = 90°.
- Let the remaining angles be 2x, 3x, 4x.
90°+ 2x + 3x + 4x = 360°9x = 360°- 90°= 270° ⇒ x = 30°* First remaining angle = 2 × 30°= 60°.
- Second remaining angle = 3 × 30°= 90°.
- Third remaining angle = 4 × 30°= 120°.
Angles of a quadrilateral are in the ratio…
एक चतुर्भुज के कोण 1 2 3 4…
- Let the angles be 1x, 2x, 3x, 4x.
1x + 2x + 3x + 4x = 360°10x = 360° ⇒ x = 36°* Angles are
- 1 × 36°= 36° 2 × 36°= 72° 3 × 36°= 108°* 4 × 36°= 144°
Adjacent angles of a parallelogram are xand x…
समान्तर चतुर्भुज के आसन्न कोण xतथा x 20हैं।…
- Sum of adjacent angles = 180°.
x + (x + 20) = 180°2x + 20 = 180° ⇒ 2x = 160° ⇒ x = 80°* First angle = 80°.
- Second angle = 80°+ 20°= 100°.
- Opposite angles are equal, so the four angles are 80°, 100°, 80°, 100°.