CG Board Class 8 Science Chapter 9 Solutions: Refraction of Light (प्रकाश का अपवर्तन) – 2026-27

CG SCERT (Chhattisgarh Board) Class 8 Science & Technology Solutions | 2026-27 Official Edition

Welcome to the complete, 100% textbook-grounded CG Board Class 8 Science Chapter 9 Solutions: Refraction of Light (प्रकाश का अपवर्तन) in Bilingual Format (English Medium + हिंदी माध्यम). Every in-text question (Answer these / इनके उत्तर दीजिए) and end-of-chapter exercise (Exercises / अभ्यास के प्रश्न) has been solved strictly from the official 2026-27 SCERT Chhattisgarh Raipur textbook.


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Question 1

When light travels from a rarer medium air…


📝 Question:

When light travels from a rarer medium (air) to a denser medium (glass), the refracted ray bends in which direction: towards the perpendicular normal or away from it? , : ?

💡 Solution:

When light travels from an optically rarer medium (air) to an optically denser medium (glass), its speed decreases. Consequently, the refracted ray bends towards the perpendicular normal (i > r).

Question 2

When light travels from a denser medium glass…


📝 Question:

When light travels from a denser medium (glass) to a rarer medium (air), the ray bends towards the perpendicular normal or away from it? , ?

💡 Solution:

When light travels from an optically denser medium (glass) to an optically rarer medium (air), its speed increases. Consequently, the refracted ray bends away from the perpendicular normal (r > i).

Question 1

What changes happen to the path of light…


📝 Question:

What changes happen to the path of light ray when it moves from denser to rarer medium? , ?

💡 Solution:

When a ray of light moves from a denser medium to a rarer medium, it speeds up and deviates away from its original path by bending away from the normal. The angle of refraction (r) becomes greater than the angle of incidence (i).

Question 2

If the light ray deviates towards the normal…


📝 Question:

If the light ray deviates towards the normal when passing from medium 1 to medium 2, what can you say about the medium being denser or rarer? 1 2 , 1 2 ?

💡 Solution:

If the light ray deviates towards the normal upon entering medium 2 from medium 1, it indicates that

  1. Medium 1 is an optically rarer medium.
  2. Medium 2 is an optically denser medium.

Question 3

A light falling perpendicular to an optical medium…


📝 Question:

A light falling perpendicular to an optical medium moves in which direction? ?

💡 Solution:

A light ray falling perpendicularly (at an angle of incidence i = 0°) on the surface of an optical medium passes straight through without any deviation or bending, continuing along the normal in the same straight direction.

Question 4

Glass is denser than water So will the…


📝 Question:

Glass is denser than water. So will the refractive index of air to glass and air to water be more or less? ?

💡 Solution:

Since glass is optically denser than water

  1. The refractive index of air to glass (μ_g ≈ 1.5) is more.
  2. The refractive index of air to water (μ_w ≈ 1.33) is less.

(Reason: Optical density is directly proportional to refractive index; higher optical density results in a higher refractive index).

S.No.Position of ObjectPosition of ImageType of ImageSize of Image
1.Beyond 2FBetween F and 2FReal and InvertedDiminished (smaller than object)
2.At 2FAt 2FReal and InvertedSame size as the object
3.Between F and 2FBeyond 2FReal and InvertedMagnified (bigger than object)
4.At F (Focus)At infinity (∞)Real and InvertedHighly magnified
5.Between F and Optical Centre OOn the same side of the objectVirtual and ErectMagnified (bigger than object)
:—::—:—:—:—
4.F(∞)
  • Table Solution (English):
Question 1

What is the minimum distance at which a…


📝 Question:

What is the minimum distance at which a clear image can be visualized? ?

💡 Solution:

The minimum distance at which an object can be clearly viewed by a normal human eye without strain is 25 cm.

Question 2

Where is the image formed in a human…


📝 Question:

Where is the image formed in a human eye? ?

💡 Solution:

In a human eye, the real and inverted image of an object is formed on the light-sensitive innermost membrane called the retina. (The image formed specifically at the yellow spot on the retina is the clearest).

Question 3

What is shortsightedness How can it be rectified


📝 Question:

What is shortsightedness? How can it be rectified? ? ?

💡 Solution:

Shortsightedness (Myopia):** It is an eye defect in which a person can see nearby objects clearly but cannot see distant objects distinctly. In this defect, the image of a distant object is formed in front of the retina rather than on it.

  • Correction: It is corrected by using spectacles fitted with a suitable double concave lens (diverging lens). The concave lens diverges incoming parallel light rays so that they focus precisely on the retina.

Question 4

What do you understand by longsightedness How can…


📝 Question:

What do you understand by longsightedness? How can this be rectified? ? ?

💡 Solution:

Longsightedness (Hypermetropia):** It is an eye defect in which a person can see distant objects clearly but cannot see nearby objects distinctly. Due to increased focal length or eye strain, the image of a nearby object is formed beyond (behind) the retina.

  • Correction: It is corrected by using spectacles fitted with a suitable convex lens (converging lens). The convex lens converges the light rays so that they focus properly on the retina.

Q11

The refractive index of glass is a 15…


📝 Question:

The refractive index of glass is:* (a) 1.5 (b) 1.3 (c) 2.4 (d) 1.0

💡 Solution:

(a) 1.5**

Q12

The point from which a light ray passes…


📝 Question:

The point from which a light ray passes without any deviation is the:* (a) Focus (b) Optical centre (c) Focal length (d) Centre of curvature

💡 Solution:

(b) Optical centre**

Q13

When light passes from one medium to another…


📝 Question:

When light passes from one medium to another, it deviates from its path. This is called:* (a) Reflection of light (b) Irregular reflection of light (c) Refraction of light (d) None of these

💡 Solution:

(c) Refraction of light**

Q14

When the object is placed at 2F the…


📝 Question:

When the object is placed at 2F, the image formed by a convex lens will be at:* (a) 2F (b) F (c) Between F and 2F (d) Between F and optical centre

💡 Solution:

(a) At 2F**

Column A: Position of ObjectColumn B: Position of ImageCorrect Match
*1. At F(1) Between F and 2F*3. At infinity
*2. Between F and 2F(2) On the side of the object*4. Beyond 2F
*3. Beyond 2F(3) At infinity*1. Between F and 2F
*4. Between F and Optical Centre(4) Beyond 2F*2. On the same side of the object
Question 1

What do you understand by refraction


📝 Question:

What do you understand by refraction? ?

💡 Solution:

When a ray of light passes obliquely from one transparent optical medium to another, it undergoes a change in its direction and speed at the boundary separating the two media. This phenomenon of bending of light rays due to a change in the medium is called refraction of light.

Question 2

When the light ray enters water medium through…


📝 Question:

When the light ray enters water medium through glass medium, where will it deflect: towards normal or away from the normal? , ?

💡 Solution:

Glass is an optically denser medium compared to water, which is an optically rarer medium (μglass ≈ 1.5 > μwater ≈ 1.33). When a light ray enters water from glass (denser to rarer medium), it speeds up and deflects away from the normal.

Question 3

What do you understand by refractive index of…


📝 Question:

What do you understand by refractive index of a medium? ?

💡 Solution:

Definition:** Refractive index (μ) is a measure of the optical density of a medium that indicates how much a ray of light bends or changes its speed when passing from one medium to another.

  • Formula: It is defined as the ratio of the velocity of light in vacuum (or air) to the velocity of light in that specific medium.

Refractive Index (μ) = (Velocity of light in vacuum / air (c))/(Velocity of light in the particular medium (v))

Question 4

Draw a ray diagram when the object is…


📝 Question:

Draw a ray diagram when the object is placed between optical centre and principal focus of a convex lens. ,

💡 Solution:

Ray Diagram Description & Features:**

When an object (AB) is placed between the optical centre (O) and principal focus (F) of a convex lens

  1. Incident Rays: One ray parallel to the principal axis refracts through focus F. A second ray passing through the optical centre O goes straight without deviation.
  2. Diverging Refracted Rays: On the other side, these rays diverge. When extended backwards (dotted lines), they meet at a point behind the object.
  3. Image Characteristics (A’B’):
  • Position: On the same side of the lens as the object.
  • Nature: Virtual and erect.
  • Size: Magnified (larger than the object).
  • Diagram Structure Representation:

`text

A’ |

| A

———-|——|——-F——-O——-F——-2F—— (Principal Axis)

| B |

B’ | | (Convex Lens)

|<--- Virtual Image --->|

Question 5

What is longsightedness How can it be rectified…


📝 Question:

What is longsightedness? How can it be rectified? Explain with diagrams. ? ?

💡 Solution:

Longsightedness (Hypermetropia):** It is a defect of vision in which a person can see distant objects clearly but cannot see nearby objects distinctly.

  • Cause: It occurs due to increase in focal length of the eye lens or shortening of the eyeball, causing the image of nearby objects to form behind the retina.
  • Correction: It is rectified using spectacles fitted with a convex lens of appropriate focal length. The convex lens converges incoming rays before they enter the eye, shifting the focus forward onto the retina.
  • Diagram Description:
  1. Defective Eye: Parallel/diverging rays from a nearby object focus beyond the retina.
  2. Corrected Eye: A convex lens placed in front of the eye bends the light rays inward so that after passing through the eye lens, they focus exactly on the retina.

`text

(a) Hypermetropic Eye (Defect)

Light Rays —> [ Eye Lens ] —> Image formed BEHIND Retina

(b) Rectification using Convex Lens

Light Rays —> ( Convex Lens ) —> [ Eye Lens ] —> Image formed ON Retina

Question 6

Explain with the help of an activity that…


📝 Question:

Explain with the help of an activity that the incident ray, the normal at the point of incidence, and the refracted ray all lie in the same plane. ,

💡 Solution:

Activity (Refraction through a Glass Slab):**

  1. Setup: Fix a white sheet of paper flat on a wooden drawing board using pins. Place a rectangular glass slab on the paper and trace its border outline (PQRS).
  2. Incident Ray & Normal: Draw an inclined line AB meeting surface PQ at point O (point of incidence). At point O, draw a perpendicular line M_1M2 representing the normal to the surface.
  3. Refraction & Outgoing Ray: Place the glass slab back. Direct light rays along AB using pins or a light streak. Mark the points C and D where the ray emerges out of surface RS at point P.
  4. Joining the Rays: Remove the glass slab and join point O to point P to obtain the refracted ray OP inside the glass slab.
  5. Observation & Conclusion:

All the drawn lines: the incident ray (AB), the normal (M_1M2) at the point of incidence O, and the refracted ray (OP) lie completely flat on the same two-dimensional plane of the paper sheet. This verifies the first law of refraction.


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