CG Board Class 10 Science Chapter 10 Solutions: Light: Reflection and Refraction from Plane Surface (प्रकाश: परावर्तन तथा अपवर्तन समतल सतह से) (2026-27)

CG Board (CGBSE / SCERT Chhattisgarh) Class 10 Science Solutions | 2026-27 New Edition (English & Hindi Medium)

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📚 Chapter Overview:

  • Board: Chhattisgarh Board of Secondary Education (CGBSE) / CG SCERT Raipur
  • Class & Subject: Class 10 Science (विज्ञान) – 2026-27 Edition
  • Chapter 10: Light: Reflection and Refraction from Plane Surface (प्रकाश: परावर्तन तथा अपवर्तन समतल सतह से)
  • CGBSE Board Weightage: 5 Marks (9 Academic Periods)
  • Medium: Bilingual Solutions (English Medium + हिंदी माध्यम)

🌐 Select Language / माध्यम चुनें:

Official Textbook Exercises

End-of-Chapter Exercises (Solutions)

Question 1

Choose the correct answer


📝 Question:

Choose the correct answer

(ii) What should be the minimum length of the plane mirror if a person wants to see his full image?

  • (a) One fourth of the person’s height
  • (b) One third of the person’s height
  • (c) Equal to the person’s height
  • (d) One half of the person’s height

(iii) How many images will be formed of an object kept between two mirrors making 45°with each other?

  • (a) 5
  • (b) 6
  • (c) 7
  • (d) 8

(iv) If an object is placed at a distance of 3 cm from the mirror, then the distance between the image and the object will be:

  • (a) 4 cm
  • (b) 6 cm
  • (c) 3 cm
  • (d) 12 cm
💡 Solution:

(i) If we rotate a plane mirror by 2θ, then the reflected ray will rotate by:**

  • (a) 2θ
  • (b) 3θ
  • (c) 4θ
  • (d) θ

(c) 4θ

Explanation: Rotating a plane mirror by an angle α rotates the reflected ray by 2α. Therefore, rotating the mirror by 2θ rotates the reflected ray by 2 × (2θ) = 4θ.

Answer: (d) One half of the person’s height

Explanation: By the laws of reflection, light rays from head and foot require a mirror height equal to half the total height of the person.

Answer: (c) 7

Explanation: Number of images n = (360°)/(θ) – 1 = (360°)/(45°) – 1 = 8 – 1 = 7.

Answer: (b) 6 cm

Explanation: Distance of image behind mirror = 3 cm. Total distance = 3 cm + 3 cm = 6 cm.

Question 2

Fill in the blanks


📝 Question:

Fill in the blanks

💡 Solution:

(i) Image formed by a plane mirror is erect, virtual and ……………………**

(ii) Second law of refraction is also known as ……………………

(iii) Light ray falls normally on plane mirror; the angle of reflection will be ……………………

(iv) For …………………… light should travel from denser medium to rarer medium.

  • (i) equal to the size of the object / body
  • (ii) Snell’s law
  • (iii) Zero (0°)
  • (iv) Total Internal Reflection

Question 3

What are the laws of reflection


📝 Question:

What are the laws of reflection?

💡 Solution:

  1. First Law: The angle of incidence (∠ i) is always equal to the angle of reflection (∠ r).

∠ i = ∠ r

  1. Second Law: The incident ray, the reflected ray, and the normal to the surface at the point of incidence all lie in the same plane.

Question 4

What are the laws of refraction


📝 Question:

What are the laws of refraction?

💡 Solution:

  1. First Law: The incident ray, the refracted ray, and the normal to the interface at the point of incidence all lie in the same plane.
  2. Second Law (Snell’s Law): The ratio of the sine of the angle of incidence (sin i) to the sine of the angle of refraction (sin r) is constant for a given pair of media

(sin i)/(sin r) = n21 = Constant

Question 5

The refractive indices of medium A and B…


📝 Question:

The refractive indices of medium A and B are n_A and n_B respectively. Total internal reflection is possible on going from which medium to which medium given that n_A > n_B?

💡 Solution:

Total internal reflection can only occur when light travels from an optically denser medium to a rarer medium. Since n_A > n_B, Medium A is denser than Medium B. Therefore, total internal reflection is possible when light travels from Medium A to Medium B.

Question 6

What is total internal reflection and what are…


📝 Question:

What is total internal reflection and what are the necessary conditions for it to take place?

💡 Solution:

Definition: When a ray of light travelling from an optically denser medium to a rarer medium is incident at an angle greater than the critical angle, the light ray is completely reflected back into the denser medium. This phenomenon is called Total Internal Reflection**.

  • Necessary Conditions:
  1. Light must travel from an optically denser medium to a rarer medium.
  2. The angle of incidence in the denser medium must be greater than the critical angle (∠ i > θ_c).

Question 7

Give two examples where refraction is seen in…


📝 Question:

Give two examples where refraction is seen in daily life

💡 Solution:

  1. A straight stick or pencil partially immersed in water appears bent at the water surface.
  2. A coin placed at the bottom of a water-filled vessel appears raised above its actual position.

Question 8

What do you understand by critical angle


📝 Question:

What do you understand by critical angle?

💡 Solution:

The critical angle (θ_c or ic) is defined as the specific angle of incidence in an optically denser medium for which the corresponding angle of refraction in the rarer medium is 90°(∠ r = 90°).

Question 9

Light travels from air to a glass slab…


📝 Question:

Light travels from air to a glass slab having a refractive index of 1.50. What will be the speed of light in glass? (Speed of light in vacuum is 3 × 108 m/s)

💡 Solution:

Given:** c = 3 × 108 m/s, Refractive index of glass ng = 1.50.

  • Formula: ng = c/vg ⇒ vg = c/ng
  • Calculation:

vg = (3 × 108)/(1.50) = 2 × 108 m/s

Question 10

Refractive index of diamond is 242 Explain this…


📝 Question:

Refractive index of diamond is 2.42. Explain this statement

💡 Solution:

The statement that the refractive index of diamond is 2.42 means that the ratio of the speed of light in vacuum to the speed of light in diamond is 2.42. In other words, light travels 2.42 times slower in diamond than in vacuum (vdiamond = (c)/(2.42) ≈ 1.24 × 108 m/s).

Question 11

A light ray travelling in the air enters…


📝 Question:

A light ray travelling in the air enters the ice. Will the light ray move away from the normal or towards the normal? Why?

💡 Solution:

The light ray will bend towards the normal. This is because ice is an optically denser medium (n = 1.31) compared to air (n = 1.0003). When light travels from an optically rarer medium to a denser medium, its speed decreases, causing it to bend towards the normal line.

Question 12

If we increase the distance between the mirror…


📝 Question:

If we increase the distance between the mirror and the object, what would be the effect on the distance between the image and the object?

💡 Solution:

If the distance between the mirror and the object (do) is increased by x, the distance between the image and the mirror (di) also increases by x. Consequently, the total distance between the object and the image (do + di = 2do) will increase by 2x (double the distance).

Question 13

What is the difference between virtual image and…


📝 Question:

What is the difference between virtual image and real image?

💡 Solution:

Question 14

What is the difference between absolute refractive index…


📝 Question:

What is the difference between absolute refractive index of a medium and relative refractive index of two mediums? What is the relation between them?

💡 Solution:

Absolute Refractive Index (n):** Ratio of speed of light in vacuum (c) to speed of light in that medium (v): n = c / v.

  • Relative Refractive Index (n21): Ratio of speed of light in Medium 1 (v1) to speed of light in Medium 2 (v2): n21 = v1 / v2.
  • Relation: The relative refractive index of Medium 2 with respect to Medium 1 is equal to the ratio of absolute refractive index of Medium 2 to that of Medium 1

n21 = n2/n1

Question 15

What is the principle of reversibility


📝 Question:

What is the principle of reversibility?

💡 Solution:

The Principle of Reversibility states that if the path of a light ray travelling through multiple media is reversed at any point, the ray retraces its entire path in the exact opposite direction.

Mathematically: {}_1n2 × {}_2n1 = 1 ⇒ {}_1n2 = frac{1}{{}_2n1}

Question 16

State the reasons for the following


📝 Question:

State the reasons for the following

💡 Solution:

(i) The position of a fish in a pond is not the same as it is observed from outside.**

(ii) An air bubble shines in water.

(iii) Mirage is an illusion.

(i)

(iii)

  • (i) Light rays from the fish travel from water (denser) to air (rarer) and bend away from the normal. When these rays enter the eye, they form a raised virtual image, making the fish appear shallower than its actual depth.
  • (ii) Light travelling in water enters the air inside the bubble at an angle greater than the critical angle for water-air interface (48.6°), undergoing Total Internal Reflection and making the bubble shine like silver.
  • (iii) On hot days, ground air gets heated and rarer while upper air remains dense. Light from distant objects continuously refracts and undergoes Total Internal Reflection from hot ground air, forming an inverted virtual image that creates the illusion of water.
  • (i) ,
  • (ii) (48.6°) ,
  • (iii) ,

Question 17

Prove that the length of the mirror required…


📝 Question:

Prove that the length of the mirror required to view the complete image of an object is half of the height of the object

💡 Solution:

Let H be the head, E be the eye, and F be the feet of a person of height HF. Light from head H reflects at point P into eye E, and light from feet F reflects at point Q into eye E.

  1. Normal PR bisects HE: RE = 1/2 HE.
  2. Normal QS bisects EF: ES = 1/2 EF.
  3. Total required mirror length PQ

PQ = RS = RE + ES = 1/2 HE + 1/2 EF = 1/2 (HE + EF) = 1/2 HF

Thus, the minimum mirror length PQ = 1/2 × Height of person.

Question 18

What do you mean by refraction of light…


📝 Question:

What do you mean by refraction of light? How is it different from reflection of light?

💡 Solution:

Refraction:** The bending of a light ray from its straight path when it passes obliquely from one transparent medium to another due to change in speed.

  • Difference:
  • Reflection: Light bounces back into the same medium from a polished surface without changing speed.
  • Refraction: Light passes into a second transparent medium with a change in speed and direction.

Question 19

If the absolute refractive index of glass is…


📝 Question:

If the absolute refractive index of glass is 3/2 and that of water is 5/4, then find the ratio of speed of light in water to that in glass

💡 Solution:

Given:** ng = 3/2, nw = 5/4.

  • Speed of light in water vw = c/nw, Speed of light in glass vg = c/ng.
  • Ratio of speed of light in water to glass:

vw/vg = (c / nw)/(c / ng) = ng/nw = 3/2/5/4 = 3/2 × 4/5 = 12/10 = 1.2

Question 20

A fish seems to be at a depth…


📝 Question:

A fish seems to be at a depth of 75 cm from the surface. What is its actual distance from the surface? (Refractive index of water is 1.33)

💡 Solution:

Given:** Apparent depth (h) = 75 cm, Refractive index of water (n) = 1.33 = 4/3.

  • Formula:

n = (Actual Depth (H))/(Apparent Depth (h))

  • Calculation:

H = n × h = 1.33 × 75 = 4/3 × 75 = 100 cm

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