CG Board Class 10 Science Chapter 11 Solutions: Chemistry of Non-Metals (अधातुओं का रसायन) (2026-27)

CG Board (CGBSE / SCERT Chhattisgarh) Class 10 Science Solutions | 2026-27 New Edition (English & Hindi Medium)

📚 Chapter Overview:

  • Board: Chhattisgarh Board of Secondary Education (CGBSE) / CG SCERT Raipur
  • Class & Subject: Class 10 Science (विज्ञान) – 2026-27 Edition
  • Chapter 11: Chemistry of Non-Metals (अधातुओं का रसायन)
  • CGBSE Board Weightage: 3 Marks (9 Academic Periods)
  • Medium: Bilingual Solutions (English Medium + हिंदी माध्यम)

🌐 Select Language / माध्यम चुनें:

Part 1

In-Text & Activity Questions

Q1

Chapter Opening Introductory Questions


📝 Question:

Chapter Opening Introductory Questions

💡 Solution:

(i) Water is made of two elements. Are these elements metals or non-metals?**

(ii) Is the gas which is essential to maintain life on earth a metal or non-metal?

(i) ?

  • (i) Water (H_2O) is composed of Hydrogen (H) and Oxygen (O). Both hydrogen and oxygen are non-metals.
  • (ii) The gas essential to maintain life on earth is Oxygen (O2), which is a non-metal.
  • (i) (H_2O) – (H) (O) **
  • (ii) (O2) , **

Q2

Section 111 Physical Properties Introductory Question You are…


📝 Question:

Section 11.1 Physical Properties Introductory Question: You are familiar with some non-metals like hydrogen, oxygen and nitrogen. Can you tell how you determined that these elements are non-metals, not metals?

💡 Solution:

Metals are generally solids at room temperature, lustrous, malleable, ductile, and good conductors of heat and electricity. Hydrogen, oxygen, and nitrogen are gases at room temperature and normal pressure, non-lustrous, non-malleable, non-ductile, and poor conductors. Therefore, based on their physical state and lack of metallic properties, we determine that they are non-metals.

Q3

Section 111 Allotropy Box Think Question You may…


📝 Question:

Section 11.1 Allotropy Box – “Think” Question: You may be aware that both graphite and diamond are forms of carbon. Both are solely made of carbon atoms. Think – how is it possible that two substances that look so different are actually forms of same substance, carbon?

💡 Solution:

This is possible because of allotropy. Although both diamond and graphite consist entirely of carbon atoms, the arrangement of carbon atoms and the nature of chemical bonding between them are different

  • In diamond, each carbon atom is covalently bonded to four other carbon atoms in a rigid three-dimensional tetrahedral network, making it extremely hard and transparent.
  • In graphite, each carbon atom is bonded to three other carbon atoms in a hexagonal planar layer structure held together by weak Van der Waals forces, making it soft, slippery, and electrically conductive.

Q4

The physical properties of four different elements are…


📝 Question:

The physical properties of four different elements are shown in the given table: – Element A: Solid, Ductile: No, Conducts electricity: No – Element B: Solid, Ductile: Yes, Conducts electricity: Yes – Element C: Gas, Ductile: No, Conducts electricity: No – Element D: Solid, Ductile: No, Conducts electricity: Yes (a) Which of the elements are metals and which are non-metals? (b) What is the criteria for deciding whether element ‘D’ is metal or non-metal?

💡 Solution:

(a)**

  • Metals: Element B (solid, ductile, conducts electricity).
  • Non-metals: Elements A, C, and D.
  • (b) Element ‘D’ is a solid that conducts electricity but is non-ductile (brittle). This exception matches graphite (an allotrope of carbon, which is a non-metal). The criteria to decide whether ‘D’ is a non-metal include its lack of ductility/malleability, brittleness, formation of acidic oxide (CO2), and electronegative nature.

Q5

Section 111 Questions Box Q2 Page 180 Which…


📝 Question:

Section 11.1 “Questions” Box – Q2 (Page 180): Which of the following exhibit allotropy? C, CO2, SO2, S, C_4H10, CH4

💡 Solution:

Allotropy is a property exhibited by elements occurring in different physical forms in the same state.

  • Elements exhibiting allotropy: Carbon (C) (diamond, graphite, fullerenes) and Sulphur (S) (rhombic, monoclinic sulphur).
  • CO2, SO2, C_4H10, CH4 are compounds, not elements, so they do not show allotropy.

Q6

Section 112 Periodic Table Position Question Can you…


📝 Question:

Section 11.2 Periodic Table Position Question: Can you tell whether an element is a metal or non-metal by looking at its position in the periodic table?

💡 Solution:

Yes. In the modern periodic table

  • Elements placed on the left side and center (Groups 1 to 12, except hydrogen) are metals.
  • Elements placed along the diagonal zig-zag line (Boron, Silicon, Germanium, Arsenic, Antimony, Tellurium, Polonium) are metalloids.
  • Elements placed on the extreme right side (Groups 14 to 18, along with Hydrogen in Group 1) are non-metals.

Q7

Section 112 InText Question Page 181 Can you…


📝 Question:

Section 11.2 In-Text Question (Page 181): Can you think of any element which is a non-metal but which has been placed on the left side in the periodic table?

💡 Solution:

Yes, Hydrogen (H) is a non-metal that is placed on the extreme left side (Group 1, Period 1) of the periodic table because of its atomic number (1) and electronic configuration (1s1).

Q8

Section 113 Questions Box Q1 Page 182 What…


📝 Question:

Section 11.3 “Questions” Box – Q1 (Page 182): What are metalloids? Give any two examples

💡 Solution:

Elements that exhibit physical and chemical properties intermediate between those of metals and non-metals are called metalloids or semi-metals. They lie along the diagonal zig-zag line separating metals and non-metals in the periodic table.

  • Examples: Silicon (Si) and Germanium (Ge) (or Boron B, Arsenic As).

Q9

Section 113 Questions Box Q2 Page 182 Give…


📝 Question:

Section 11.3 “Questions” Box – Q2 (Page 182): Give reasons why gaseous elements were discovered quite late as compared to solid elements

💡 Solution:

Gaseous elements were discovered much later than solid elements because

  1. Gases are invisible, colorless, and odorless, making them difficult to detect visually or isolate in pure forms without specialized apparatus.
  2. The techniques and equipment required to produce, trap, and collect gases over liquids (such as the pneumatic trough developed by Hales in the mid-18th century) were not available in ancient times.
  3. Lack of early understanding of the gaseous state and its role in chemical reactions prevented early scientists from recognizing gases as distinct elements.

Q10

Section 113 Questions Box Q3 Page 182 The…


📝 Question:

Section 11.3 “Questions” Box – Q3 (Page 182): The elements of group 18 do not normally take part in chemical reactions, why?

💡 Solution:

The elements of Group 18 (noble or inert gases like He, Ne, Ar, Kr, Xe, Rn) have completely filled outermost valence shells containing 8 electrons (octet completed, or duplet of 2 electrons in Helium). Because their electronic configurations are extremely stable, they have no tendency to gain, lose, or share electrons, making them chemically inert under normal conditions.

Q11

Activity1 Sulphur Burning Question Page 183184 Did you…


📝 Question:

Activity-1 Sulphur Burning Question (Page 183-184): Did you observe any change in colour of litmus paper when tested with the aqueous solution of sulphur dioxide gas?

💡 Solution:

Yes. When sulphur burns in air, it forms sulphur dioxide gas (SO2). When SO2 is dissolved in water, it forms sulphurous acid (H_2SO3). This solution turns moist blue litmus paper RED, while red litmus paper remains unchanged. This proves that sulphur dioxide is an acidic oxide.

S(s) + O2(g) → SO2(g)

SO2(g) + H_2O(l) → H_2SO3(aq) (Sulphurous acid)

Q12

Section 1143 Questions Box Q1 Page 184 Look…


📝 Question:

Section 11.4.3 “Questions” Box – Q1 (Page 184): Look up the names of different acids used in the laboratory and find out the non-metals that make them up

💡 Solution:

  1. Hydrochloric Acid (HCl): Hydrogen (H) and Chlorine (Cl).
  2. Sulphuric Acid (H_2SO4): Hydrogen (H), Sulphur (S), and Oxygen (O).
  3. Nitric Acid (HNO3): Hydrogen (H), Nitrogen (N), and Oxygen (O).
  4. Carbonic Acid (H_2CO3): Hydrogen (H), Carbon (C), and Oxygen (O).

Q13

Section 1143 Questions Box Q2 Page 184 Nonmetals…


📝 Question:

Section 11.4.3 “Questions” Box – Q2 (Page 184): Non-metals are electronegative, why?

💡 Solution:

Non-metals have 4, 5, 6, or 7 electrons in their outermost valence shell. Due to their relatively small atomic radii and high effective nuclear charge, non-metals have a strong tendency to gain electrons to achieve a stable octet noble gas configuration, forming negative ions (anions). Hence, non-metals are electronegative in nature.

Q14

Section 1143 Questions Box Q3 Page 184 You…


📝 Question:

Section 11.4.3 “Questions” Box – Q3 (Page 184): You are given an element; how will you identify whether it is a metal or non-metal? Give three means

💡 Solution:

  1. Malleability/Brittleness Test: Hammer the solid element. If it flattens into a thin sheet without breaking, it is a metal. If it crumbles into powder (brittle), it is a non-metal.
  2. Electrical Conductivity Test: Connect the element into a circuit with a battery and bulb. If the bulb glows (good conductor), it is a metal (except graphite exception). If it does not conduct electricity, it is a non-metal.
  3. Nature of Oxide Test: Burn the element in air and dissolve its oxide in water. Test with litmus paper. If the solution turns red litmus blue (basic oxide), the element is a metal. If it turns blue litmus red (acidic oxide), the element is a non-metal.

Q15

Section 115 Hydrogen Introductory Question Consider the names…


📝 Question:

Section 11.5 Hydrogen Introductory Question: Consider the names hydrogen, oxygen and nitrogen. Do you notice any similarities in the names?

💡 Solution:

Yes, all three names end with the suffix “-gen”. The suffix “-gen” is derived from the Greek word genes, which means ‘one which produces’ or ‘generator of’

  • Hydro-gen: Water producer (hydro = water).
  • Oxy-gen: Acid producer (oxy = acid).
  • Nitro-gen: Nitre/saltpetre producer (nitro = nitre).

Q16

Section 1151 Laboratory Preparation of Hydrogen Questions


📝 Question:

Section 11.5.1 Laboratory Preparation of Hydrogen Questions

💡 Solution:

(i) Write the balanced chemical equation for the reaction between granulated zinc and hydrochloric acid.**

(ii) Activity-2 Question: How will you test that the gas collected by the displacement of water is hydrogen?

(i)

  • (i) Balanced Chemical Equation:

Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)↑

  • (ii) Test for Hydrogen Gas:

Bring a burning matchstick near the mouth of the test tube containing the gas. Hydrogen gas burns rapidly with a characteristic ‘pop’ sound, confirming its presence. (Precaution: Do not insert matchstick inside).

  • (i) :
  • (ii) :

Q17

Section 1152 Chemical Properties Equation Completion Complete the…


📝 Question:

Section 11.5.2 Chemical Properties Equation Completion: Complete the following equations and balance them: – H2( ) + Br2( ) → ? – H2( ) + F2( ) → ?

💡 Solution:

  1. H2(g) + Br2(g) → 2HBr(g) (Hydrogen bromide)
  2. H2(g) + F2(g) → 2HF(g) (Hydrogen fluoride)

Q18

Section 1171 Oxygen Preparation Activity4 Question How will…


📝 Question:

Section 11.7.1 Oxygen Preparation Activity-4 Question: How will you test whether the collected gas obtained by heating potassium permanganate is oxygen?

💡 Solution:

Bring a glowing wooden splint near the mouth of the test tube containing the collected gas. If the glowing splint immediately bursts into a bright flame, the gas is confirmed to be Oxygen (O2), because oxygen supports combustion.

Q19

Section 1173 Questions Box Q1 Page 190 Write…


📝 Question:

Section 11.7.3 “Questions” Box – Q1 (Page 190): Write the balanced chemical equations for reactions of calcium, lithium and aluminium with hydrogen

💡 Solution:

  1. Reaction with Calcium (Ca):

Ca(s) + H2(g) → CaH2(s) (Calcium hydride)

  1. Reaction with Lithium (Li):

2Li(s) + H2(g) → 2LiH(s) (Lithium hydride)

  1. Reaction with Aluminium (Al):

2Al(s) + 3H2(g) → 2AlH3(s) (Aluminium hydride)

Q20

Section 1173 Questions Box Q2 Page 190 Which…


📝 Question:

Section 11.7.3 “Questions” Box – Q2 (Page 190): Which gas is used in packaged foods and why?

💡 Solution:

Nitrogen gas (N2)** is filled in packaged food containers and potato chip packets.

  • Reason: Nitrogen provides an unreactive, inert atmosphere that replaces oxygen gas, preventing the oxidation (rancidity) of oils and fats present in food, thereby keeping the food fresh and crisp for a long time.

Q21

Section 1173 Questions Box Q3 Page 190 In…


📝 Question:

Section 11.7.3 “Questions” Box – Q3 (Page 190): In laboratories, oxygen is collected in an upturned, water-filled test tube or gas jar, why?

💡 Solution:

Oxygen gas is collected over water by the downward displacement of water because

  1. Oxygen is only very slightly soluble (sparingly soluble) in water, so it does not dissolve significantly during collection.
  2. It prevents oxygen from mixing with atmospheric air, yielding pure gas.

Part 2

End-of-Chapter Exercise Solutions

Q1

Choose the correct option


📝 Question:

Choose the correct option

💡 Solution:

(i) The solution in water of which of the following will be acidic:**

  • (a) Na_2O
  • (b) CO2
  • (c) MgO
  • (d) H_2O

(b) CO2

Explanation: Carbon dioxide (CO2) is a non-metallic oxide that dissolves in water to form carbonic acid (H_2CO3), turning blue litmus red. Na_2O and MgO form basic solutions, while H_2O is neutral.

(ii) Which of the following elements does not exhibit allotropy:

  • (a) Sodium
  • (b) Oxygen
  • (c) Sulphur
  • (d) Phosphorus

Answer: (a) Sodium

Explanation: Sodium is a metal that exists in a single crystalline form and does not show allotropy. Oxygen (O2, O3), Sulphur (rhombic, monoclinic), and Phosphorus (white, red, black) exhibit allotropy.

(iii) Which among the following is a metalloid:

  • (a) Oxygen
  • (b) Helium
  • (c) Magnesium
  • (d) Arsenic

Answer: (d) Arsenic

Explanation: Arsenic (As) lies along the diagonal zig-zag line of the periodic table and exhibits intermediate properties between metals and non-metals.

(iv) Noble gases do not react with other elements because:

  • (a) They are monoatomic gases
  • (b) Their atomic size is small
  • (c) Their outermost shell is full
  • (d) They are found in abundant amounts

Answer: (c) Their outermost shell is full

Explanation: Noble gases have a complete octet (or duplet for He) in their outermost valence shell, rendering them stable and chemically unreactive.

(v) The gas obtained on heating potassium permanganate is:

  • (a) Nitrogen
  • (b) Oxygen
  • (c) Hydrogen
  • (d) Helium

Answer: (b) Oxygen

Explanation: Thermal decomposition of potassium permanganate (KMnO4) yields oxygen gas: 2KMnO4 → [Δ] K_2MnO4 + MnO2 + O2↑.

Q2

Fill in the blanks


📝 Question:

Fill in the blanks

💡 Solution:

(i) The most electronegative element is …………….. (chlorine/ fluorine).**

(ii) Carbon is ………… (more/less) reactive as compared to oxygen.

(iii) Non-metals are found at the …………….(right/ left) side of the periodic table.

(iv) ……………….. (hydrogen/ nitrogen) gas is obtained when granulated zinc is reacted with dilute acid or alkali.

  • (i) fluorine
  • (ii) less
  • (iii) right
  • (iv) hydrogen

Q3

Compare the physical properties of metals and nonmetals


📝 Question:

Compare the physical properties of metals and non-metals

💡 Solution:

1. : (C, S, P), (Br2), (H2, O2, N2)
3. ;
4.
5.
6. (Sonorous)

Q4

Write the balanced chemical equations for formation of…


📝 Question:

Write the balanced chemical equations for formation of chlorides and oxides of the following elements: Hydrogen, Phosphorous, Sodium, and Magnesium

💡 Solution:

  1. Hydrogen (H2):
  • Chloride: H2(g) + Cl2(g) → 2HCl(g)
  • Oxide: 2H2(g) + O2(g) → 2H_2O(l)
  1. Phosphorus (P4):
  • Chloride: P4(s) + 6Cl2(g) → 4PCl3(l)
  • Oxide: P4(s) + 5O2(g) → P_4O10(s)
  1. Sodium (Na):
  • Chloride: 2Na(s) + Cl2(g) → 2NaCl(s)
  • Oxide: 4Na(s) + O2(g) → 2Na_2O(s)
  1. Magnesium (Mg):
  • Chloride: Mg(s) + Cl2(g) → MgCl2(s)
  • Oxide: 2Mg(s) + O2(g) → 2MgO(s)

Q5

Write the equation and corresponding conditions for reaction…


📝 Question:

Write the equation and corresponding conditions for reaction between nitrogen and hydrogen

💡 Solution:

Nitrogen and hydrogen react to produce Ammonia gas (NH3) via Haber’s Process.

  • Balanced Chemical Equation:

N2(g) + 3H2(g) ⇌ [450°C-500°C, 200 atm / Fe catalyst, Mo promoter] 2NH3(g)

  • Reaction Conditions:
  1. Temperature: 450°C – 500°C
  2. Pressure: 200 atm (high pressure)
  3. Catalyst: Finely divided Iron (Fe)
  4. Promoter: Molybdenum (Mo) (increases catalyst efficiency)

Q6

Hydrogen can be placed either in group 1…


📝 Question:

“Hydrogen can be placed either in group 1 or in group 17”. Do you agree with this statement or disagree? Give reasons

💡 Solution:

Yes, we agree with this statement.** Hydrogen shows dual characteristics resembling both Group 1 alkali metals and Group 17 halogens

  1. Resemblance with Group 1 (Alkali Metals):
  • Electronic configuration: Contains 1 electron in the outermost shell (1s1).
  • Electropositive character: Can lose 1 electron to form a monovalent positive ion (H^+).
  • Combines with non-metals (oxygen, sulphur, halogens) to form compounds like H_2O, H_2S, HCl.
  1. Resemblance with Group 17 (Halogens):
  • Requires 1 electron to complete its nearest noble gas configuration (He).
  • Electronegative character: Can gain 1 electron to form a hydride ion (H^-), forming ionic hydrides (NaH, CaH2) with active metals.
  • Diatomic molecule: Exists as a diatomic gas (H2), similar to F2, Cl2, Br2.
  • Non-metallic nature and high ionization energy.

Q7

Why are helium neon krypton argon xenon and…


📝 Question:

Why are helium, neon, krypton, argon, xenon and radon known as inert gases?

💡 Solution:

Helium, neon, argon, krypton, xenon, and radon belong to Group 18 of the periodic table. They are called inert gases (or noble gases) because their outermost valence shells are completely filled with 8 electrons (octet completed; Helium has a duplet of 2 electrons). Due to this fully-filled stable electronic configuration, they have zero valency and no chemical affinity to gain, lose, or share electrons, remaining unreactive under normal conditions.

Q8

Explain the following industrial uses of hydrogen a…


📝 Question:

Explain the following industrial uses of hydrogen: (a) Heat production on combustion **(b) Reaction with vegetable oils in the presence of a catalyst

💡 Solution:

(a) Heat Production on Combustion:**

  • Hydrogen gas has a very high calorific value and burns cleanly in oxygen to release immense thermal energy without emitting carbon pollutants

2H2(g) + O2(g) → 2H_2O(g) + Energy

  • Industrial uses: Oxy-hydrogen flames (2800°C) are used for welding and cutting metals. Liquid hydrogen is used as high-energy rocket fuel and in fuel cells to generate electrical energy and heat.
  • (b) Reaction with Vegetable Oils (Hydrogenation):
  • Unsaturated organic compounds in vegetable oils contain carbon-carbon double bonds (C=C). When hydrogen gas is passed through liquid vegetable oil at 150°C-200°C in the presence of a Nickel (Ni) catalyst, the double bonds are converted into single bonds (C-C).
  • Industrial process:

Unsaturated Vegetable Oil + H2 → [Ni Catalyst / 150°C-200°C] Saturated Vegetable Fat (Vanaspati Ghee)

  • This process is called Hydrogenation of Oils and is used to manufacture solid vegetable ghee from liquid oils.

Q9

What happens when potassium permanganate is heated Explain…


📝 Question:

What happens when potassium permanganate is heated? Explain giving balanced equation

💡 Solution:

When dark purple crystals of Potassium Permanganate (KMnO4) are heated, thermal decomposition takes place, producing Potassium Manganate (K_2MnO4), Manganese Dioxide (MnO2), and Oxygen gas (O2).

  • Balanced Chemical Equation:

2KMnO4(s) → [Δ] K_2MnO4(s) + MnO2(s) + O2(g)↑

Q10

Gas A is formed when granulated zinc reacts…


📝 Question:

Gas ‘A’ is formed when granulated zinc reacts with dilute hydrochloric acid. It reacts with oxide ‘B’ and reduces it to copper metal. Write the names of ‘A’ and ‘B’ and also give the equations for the described reactions

💡 Solution:

Identification:**

  • Gas ‘A’: Hydrogen gas (H2)
  • Oxide ‘B’: Copper(II) Oxide / Cupric Oxide (CuO)
  • Chemical Equations:
  1. Formation of Gas ‘A’ (Hydrogen):

Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)↑ (Gas ‘A’)

  1. Reduction of Oxide ‘B’ (Copper Oxide) by Gas ‘A’:

CuO(s) (Oxide ‘B’) + H2(g) (Gas ‘A’) → [200°C] Cu(s) + H_2O(g)

Q11

Sevati took sulphur powder in deflagrating spoon heated…


📝 Question:

Sevati took sulphur powder in deflagrating spoon, heated it and collected the gas formed in a test tube. What will happen when moist red and blue litmus papers are taken near the mouth of the test tube and why? Write the chemical equations for the reactions taking place

💡 Solution:

Observation & Reason:**

  • Moist Blue Litmus Paper turns RED.
  • Moist Red Litmus Paper remains RED (no change).
  • Reason: Burning sulphur powder produces Sulphur Dioxide gas (SO2). When SO2 reacts with moisture on the litmus paper, it forms Sulphurous acid (H_2SO3). Being an acidic solution, it turns blue litmus paper red.
  • Chemical Equations:
  1. Combustion of Sulphur

S(s) + O2(g) → SO2(g)

  1. Reaction of SO2 with moisture

SO2(g) + H_2O(l) → H_2SO3(aq) (Sulphurous acid)

Q12

The processes described below are due to which…


📝 Question:

The processes described below are due to which property of hydrogen: (a) A hydrogen filled balloon floats in air. **(b) A ‘pop’ sound is heard when a lighted matchstick is taken near the mouth of a hydrogen filled gas jar

💡 Solution:

(a) This is due to the extremely low density** of hydrogen gas. Hydrogen is the lightest of all known elements and is much less dense than surrounding atmospheric air, providing upward buoyant force.

  • (b) This is due to the extreme combustibility (flammability) of hydrogen gas. When hydrogen reacts rapidly with oxygen in the presence of a flame, a localized miniature explosion produces a characteristic ‘pop’ sound.

Q13

Compound X which is used for drinking has…


📝 Question:

Compound X, which is used for drinking, has pH value 7. Electrolysis of an acidic solution of X gives gases Y and Z. The volume of Y is twice that of Z. Y burns rapidly while Z supports burning. Identify X, Y and Z and write the equations for the described reactions

💡 Solution:

Identification:**

  • Compound X: Water (H_2O) (Neutral liquid, pH = 7, used for drinking).
  • Gas Y: Hydrogen gas (H2) (Evolved at cathode, volume is double, highly combustible).
  • Gas Z: Oxygen gas (O2) (Evolved at anode, half volume of Y, supports combustion).
  • Chemical Equation for Electrolysis:

2H_2O(l) → [Electrolysis / Acidified] 2H2(g)↑ (Gas Y, Cathode) + O2(g)↑ (Gas Z, Anode)

(Mole / Volume ratio of Y : Z = 2 : 1)


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